Answer:
Final molarity of iodide ion C(I-) = 0.0143M
Explanation:
n = (m(FeI(2)))/(M(FeI(2))
Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol
So n = 0.981/309.85 = 0.0031 mol
V(solution) = 150mL = 0.15L
C(AgNO3) = 35mM = 0.035M = 0.035m/L
n(AgNO3) = C(AgNO3) x V(solution)
= 0.035 x 0.15 = 0.00525 mol
(AgNO3) + FeI(3) = AgI(3) + FeNO3
So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol
C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M
Answer:
what is the formula of rectangle
Answer:
CH3CH2CH2CH2CH2OH.
Explanation:
Hello.
In this case, since the vapor pressure is known to be the pressure exerted by the gaseous molecules in equilibrium with a liquid, we can infer that the higher the molecule, the lower the vapor pressure because the molecules tend to be help together more strongly and more energy is required to separate them and take them from liquid to gas.
In such a way, since CH3CH2CH2CH2CH2OH is the longest molecule (five carbon atoms) it would be more stable at liquid phase which means that it has less molecules moving to gaseous phase, which is also related with the lowest vapor pressure. Conversely, CH3CH2OH has the highest vapor pressure.
Best regards.
C₃H₈ + 5 O₂ → 4 H₂O + 3 CO₂
mole ratio based on balance equation of O₂ : CO₂ i s 5 : 3
C₃H₈ + 5 O₂ → 4 H₂O + 3 CO₂
∴ if moles of CO₂ = 3 moles
then moles of O₂ = (3 moles ÷ 3) × 5
= <span>5 moles </span>
