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Annette [7]
4 years ago
9

a known mass of solute is dissolved in a known mass of water and the total volume is determined. The molar mass of the solute ca

n be determined by measuring which other quantity?
Chemistry
1 answer:
kotykmax [81]4 years ago
5 0

Explanation:

Properties of a solution which are dependent on the ratio of number of solute particles to the number of solvent molecules in a solution are known as colligative properties.

Lowering of vapor pressure and elevation in boiling point are basically two of the colligative properties which indirectly help to measure the molecular weight of a substance.

Thus, we can conclude that molar mass of the solute can be determined by measuring lowering of vapor pressure and elevation in boiling point.

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Help please
kipiarov [429]

The correct options are these:

1. It will follow the law of conservation of mass.

2.The mass of products will be equal to the mass of the reactants.

The law of conservation of mass states that ' matter can neither be created nor destroyed. Thus, if a chemical equation is balanced, the mass of the reactant at the beginning of the reaction will be equal to the mass of the product after the reaction. This shows that the chemical reaction obeys the law of conservation of mass.

6 0
3 years ago
Read 2 more answers
When determining if a bond is polar, we must evaluate the difference in electronegativity (δen) of the atoms involved in the bon
Anastasy [175]
True

The electronegativity of an atom is the tendency of an atom in a compound or molecule to attract bonding electrons unto itself. A polar bond is formed when there is an uneven distribution of charges in the molecule brought about by differences in the electronegativities of the atoms in the bonds. These differences create regions of partially positive and partially negative charges. A nonpolar bond only have very small differences in the electronegativity of the bonding atoms. 

Generally, when the difference in electronegativity is less than 0.5, the bond is polar. When the difference is between 0.5 and 1.7, the bond is polar. Finally, when the difference is greater than 1.7, the bond is ionic, which means that the bonding electron is very much attracted to the highly electronegative atom that it is transferred to the said atom instead of merely being shared by the atoms in the bond. 
8 0
3 years ago
The equilibrium constant Kp for the reaction I2(g) + Br2(g) ⇀↽ 2 IBr(g) + 11.7 kJ is 280 at 150◦C. Suppose that a quantity of IB
mixas84 [53]

Answer:

\large \boxed{\text{0.0120 atm }}

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

      Kp = 280

p(IBr) = 0.200 atm

1. Set up an ICE table.

Let p = the initial pressure of IBr. Then

\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} &  &  \\0 & & 0 & & p & & \\+x &   & +x  & & -2x &   &\\x &   & x} &   & 280 & & \\\end{array}

2. Calculate p(I₂)

\begin{array}{rcl}K_{\text{p}}&=&\dfrac{p_{\text{IBr}}^{2}} {p_{\text{I}_2}^{2}}\\\\280&=&{\dfrac{0.200^{2}}{x^{2}}&&\\\\280x^{2} & = &0.0400\\x^{2} & = &\dfrac{0.0400}{280 }\\\\& = & 1.429 \times 10^{-4}\\x & = & \textbf{0.0120 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.0120 atm }}$}}

Check:

\begin{array}{rcl}{\dfrac{0.200^{2}}{0.0120^{2}}}&=&280\\\\280& =& 280\\\end{array}

8 0
3 years ago
What is a fossil?
katrin2010 [14]
The remains of an animal or plant preserved within a layer of rock I think I’m sorry if I’m wrong
6 0
3 years ago
If you have 35 ml of gas in a closed container under 1.23 atm of pressure, what will the volume be if the pressure increased to
Over [174]

Answer:

New volume is 14.35 mL

Explanation:

When a system of a gas keeps on constant its temperature and number of moles, the pressure is modified indirectly proportional to the volume:

Pressure increased → Volume decreased

Pressure decreased → Volume increased.

The relation you have to apply is: P₁ . V₁ = P₂. V₂

1.23 atm . 35 mL = 3 atm . V₂

(1.23 atm . 35 mL / 3 atm)  = V₂

V₂ = 14.35 mL

5 0
3 years ago
Read 2 more answers
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