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3 years ago

Simplify -2(-4x + 5)

Mathematics

1 answer:

Bingel [31]3 years ago

3 0

Answer:

the answer would be 8x-10

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V= u + at u= 2 a = -5 t = 1 글 Work out the value of v.

Maksim231197 [3]

Answer:

v = - 3

Step-by-step explanation:

Given

v = u + at ← substitute u = 2, a = - 5, t = 1 into the expression

v = 2 + (- 5 × 1) = 2 + (- 5) = 2 - 5 = - 3

5 0

3 years ago

Please help pleaaaseee it’s a little test but I need help please!!

Wewaii [24]

Answer:

$JT = 3\sqrt{2}, JE = 3$

Step-by-step explanation:

This is a 45-45-90 triangle

6 0

3 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

Simplify 16 - 12 ÷ 4 +3 (6-2) show working plz

ira [324]

Answer:

Step-by-step explanation:

16-12/4+3(6-2) subtract 6 and 2

16-12/4+3+4 divide 12 and 4

16-3+3+4 subtract 16 and 3

13+3+4 add all 3 numbers

13+7

4 0

3 years ago

I kinda need help on this! which ordered pair represents the coordinates of point H

Alex73 [517]

I believe it is the last answer choice

7 0

3 years ago