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Tema [17]
3 years ago
7

Which value for x makes the sentence true? x/4 - 9 = 5​

Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Answer:

I might be wrong but i think it is 46

Step-by-step explanation:

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HELPPPPP ASP PLZZZZZ
-Dominant- [34]

Answer:

(f-g)(x)

f(x)-g(x)

x^{2} -6x-27-x+9

x^{2} -7x-18

----------------------

(f*g)(x)

=f(x)g(x)

(x^{2} -6x-27)(x-9)

=x^{3} -15x^{2}+27x+243

----------------------

\frac{f}{g} (x)

\frac{x^{2} -6x-27}{x-9}

\frac{(x-9)(x+3)}{x-9}

x+3

-----------------------

(f+g)(x)

f(x)+g(x)

=x^{2} -6x-27+x-9

=x^{2} -5x-36

------------------------

<u>OAmalOHopeO</u>

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5 0
3 years ago
I don’t understand how to do this.
yan [13]

Answer:

46degrees

Step-by-step explanation:

From the question, we are told that both triangles are similar, hence;

<E = <S

<D = <R

<F = <T

From triangle DEF

<D + <F + <E = 180

Since <D = <F = 67

67 + 67 + <E = 180

134 + <E = 180

<E = 180 - 134

<E = 46degrees

Since <E = <S, hence the measure of <S  is 46degrees

8 0
3 years ago
The table shows the heights of students in a group
8_murik_8 [283]

Answer:

Mean=(46+48+51+53)/4

Mean=198/4

Mean=49.5

Step-by-step explanation:

Mean is the total amount per the total number of terms. It is also known as average.

8 0
3 years ago
Read 2 more answers
Find two ratios equivalent to the ratio 8:5
kiruha [24]
16:10 and also 24:15
7 0
3 years ago
Read 2 more answers
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
3 years ago
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