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3 years ago

Can someone please answer. There is one problem. There's a picture. Thank you!

Mathematics

1 answer:

Katen [24]3 years ago

7 0

Circumference of the circle = 2πr
32 = 2*22/7*r
32*7/2*22 =r
5.09 =r
5.1 (approx) = r

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a pyramid with a square base that is 9 cm on a side has a height of 10 cm the volume of the pyramid is

Zanzabum

$\bf \textit{volume of a pyramid}\\\\
V=\cfrac{1}{3}Bh~~
\begin{cases}
B=area~of\\
\qquad its~base\\
h=height\\[-0.5em]
\hrulefill\\
B=\stackrel{9\times 9}{81}\\
h=10
\end{cases}\implies V=\cfrac{1}{3}(81)(10)\implies V=270$

4 0

3 years ago

Diego buys 4.25 pounds of mushrooms. Each pound costs $2.99. Which expression gives the best estimate of the cost of the mushroo

Vadim26 [7]

Answer:

(4)($3)

Step-by-step explanation:

Given parameters:

Quantity of mushroom bought = 4.25pounds

Cost of each mushroom = $2.99

Unknown:

Best estimate for the cost of the mushroom = ?

Solution:

The cost of the mushroom is:

Total cost = quantity of mushroom bought x cost of each mushroom

Total cost = 4.25 x 2.99

You can round 4.25 to 4 and 2.99 to 3

Or 4 x 3 = $12

8 0

3 years ago

Read 2 more answers

How to solve 3/2=2x this problem

poizon [28]

Step-by-step explanation:

3/2 is 1½ so that means 1½ divided by 2 is <em><u>3/4</u></em>

3 0

3 years ago

What is the distance between (-1,-3),(1,3)

Harlamova29_29 [7]

Answer:

4,4 is the distance

Step-by-step explanation:

cause its 4 squares away for both

3 0

2 years ago

Read 2 more answers

A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.

IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car ( $v_0$ ) = 40 ft/sec

Deceleration of the car ( $\frac{dv}{dt}$ ) = -10 ft/sec²

Final speed of the car ( $v_x$ ) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, $\frac{dv}{dt}=-10\ ft/sec^2$

Negative sign means the velocity is decreasing with time.

Now, $\frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt})$ using chain rule of differentiation. Therefore,

$\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx$

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

$\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft$

Therefore, the car travels a distance of 80 feet before stopping.

4 0

3 years ago