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3 years ago

PLEASE PLEASE PLEASE HELP

Mathematics

1 answer:

mr Goodwill [35]3 years ago

5 0

Step-by-step explanation:

25 - 19.28 = 5.72

5.72 × 100 to change from dollar to cents

572

572 ÷ 13 = 44 yards of ribbon karen bought

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Find the measure of each acute angle in a right triangle where the measure of one acute angle is 3 times the sum of the measure

expeople1 [14]

Answer:

α = 20.5

β = 69.5

c = 90

Step-by-step explanation:

we have to make 2 equations one for the relationship between the angles and another for the sum of all the angles

β and α are the acute angles

β = 3α + 8

α + β + 90 = 180

we replace in the second equation the value of β by (3α + 8)

α + β + 90 = 180

α + (3α + 8) + 90 = 180

a + 3a = 180 - 90 - 8

4a = 82

a = 82/4

a = 20.5

now we replace the value of b in the other equation

β = 3α + 8

β = 3 * 20.5 + 8

β = 69.5

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

20% of 45 marbles is __marbles. *

kykrilka [37]

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3 years ago

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A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other w

hoa [83]

Answer:

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

Step-by-step explanation:

Volume of cylinder = V

Radius of cylinder = r = 0.5 m

Height of the cylinder = 5 m

Volume of cylinder = $\pi r^2h$

$V=3.14\times (0.5 m)^2\times 5 =3.925 m^3$

Mass of gasoline = m

Density of gasoline = d = $673 kg/m^3$

$m=d\times V=673 kg/m^3\times 3.925 m^3=2,641.525 kg$

Work done to pump the gasoline out of the tank W

Acceleration due to gravity = g $.8 m/s^2$

The center of gravity of fuel in fully filled tank will be centre so, the value of h = 2 m + 0.5 m = 2.5 m

$W =m\times g\times h$

$W=2,641.525 kg\times 9.8 m/s^2\times 2.5 m=64,717.36 J$

64,717.36 Joule is the total amount of work needed to pump the gasoline out of the tank.

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3 years ago