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lutik1710 [3]
3 years ago
5

Ashley's Internet service is terribly unreliable. In fact, on any given day, there is a 15% chance that her Internet connection

will be lost at some point that day. What is the probability that her Internet service is not broken for five days in a row
Mathematics
1 answer:
stepan [7]3 years ago
6 0

Answer:.3 .3 .3 .3 .3 *.3 = .0007

Step-by-step explanation:

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What is 1 hundredth + 3 tenths=
musickatia [10]
Answer is 0.31. Hope this helps.
6 0
3 years ago
Chuanxi planned a rectangular sidewalk with a length of 21 ft. He made a scale drawing using a scale factor of 1 in. = 7 ft. He
Masteriza [31]
Original Ratio of 1 in = 7 ft so 3 in = 21 ft
Now, New ratio 1 in = x ft so 3 in = 27ft

1/x = 3/27

cross multiply a/b = c/d ad = bc
1/x = 3/27
3x = 27
x = 9

1 in represents 9 ft
7 0
4 years ago
Read 2 more answers
A study of the amount of time it takes a mechanic to rebuild the transmission for a 1992 Chevrolet Cavalier shows that the mean
Dovator [93]

Answer:

B) 0.0069

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846

Find the probability that their mean rebuild time exceeds 9.1 hours.

This is 1 subtracted by the pvalue of Z when X = 9.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{9.1 - 8.4}{0.2846}

Z = 2.46

Z = 2.46 has a pvalue of 0.9931

1 - 0.9931 = 0.0069

So the answer is B.

6 0
3 years ago
(Figure is provided below)
DanielleElmas [232]

Answer:

The measure of ∠z   = 137°

Step-by-step explanation:

Here, angle 1  = 43°

To find : ∠z

Straight line Angle:  The angle which measures exactly 180° and is extended by a point on a straight line is called straight angle.

According to the given figure:

  ∠1 + ∠z  = 180 °  (STRAIGHT LINE ANGLE)

or,   ∠z  = 180 ° - 43° = 137°

Hence, the measure of ∠z   = 137°.

7 0
3 years ago
Paint manufacturer uses a machine to fill 1- gallon cans with paint- they want to estimate the mean volume of paint the machine
Triss [41]

Answer:

n=(\frac{1.64(0.85)}{0.25})^2 =31.09

So the answer for this case would be n=32 rounded up to the nearest integer

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=0.85 represent the sample standard deviation

n represent the sample size (variable of interest)  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}  

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (1)

And on this case we have that ME =0.25 and we are interested in order to find the value of n, if we solve n from equation (1) we got:

n=(\frac{z_{\alpha/2} s}{ME})^2   (2)

The critical value for 90% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.05,0,1)", and we got z_{\alpha/2}=1.64, replacing into formula (2) we got:

n=(\frac{1.64(0.85)}{0.25})^2 =31.09

So the answer for this case would be n=32 rounded up to the nearest integer

5 0
3 years ago
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