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mrs_skeptik [129]
3 years ago
14

Find the distance between the two points rounding to the nearest tenth! PLEASE HELP ASAP!!! :

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0
(-6,-5) (1,-8)
d= √(x₂−x₁)² +(y₂−y₁)²
d= √(1+6)² +(-8+5)²
d= √(7)² +(-3)²
d= √49+9
d= √51
d=7.1
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PLEASE HELP ME WITH THIS QUESTION!!
marin [14]

Answer:

+$90;

$1,600

Step-by-step explanation:

The equation, y = 1600 + 90x, given to us tells us much about the situation described above.

y = total pay

x = number of copies of Math is fun

1600 = y-intercept, that is the starting value or the pay he gets only if Sam sold 0 copy of Math is fun. That is, when x = 0, y = 1,600.

90 = unit rate or the change in the total pay for each copy of Math is fun that Sam sells.

Therefore, our answers would be:

+$90, and $1,600

5 0
3 years ago
A triangular towelette has a base of 2 inches and a height of 3 inches. What is the area of a towelette with double the base and
zysi [14]
A triangle with a base of 2 and a height of 3.

Double the base and it becomes 4, and double the height and it becomes 6.

Area of the new figure = 1/2 * base * height = 1/2 * 4 * 6 = 2 * 6 = 12

The area of a towelette with double the base and double the height is 12 inches^2.
8 0
3 years ago
A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears
arsen [322]

Answer:

The correct answer is "0.0000039110".

Step-by-step explanation:

The given values are:

Y_n\rightarrow N(\mu, \sigma^2)

\mu = 40n

\sigma^2=100n

n=20

then,

The required probability will be:

= P(Y_{20}>1000)

= P(\frac{Y_{20}-\mu}{\sigma} >\frac{1000-40\times 20}{\sqrt{100\times 20} } )

= P(Z>\frac{1000-800}{44.7214} )

= P(Z>\frac{200}{44.7214} )

= P(Z>4.47)

By using the table, we get

= 0.0000039110

6 0
3 years ago
All four B points are equidistant from points A and C. Are they all midpoints of AC? Justify your answer.
Rina8888 [55]

Answer:

No

Step-by-step explanation:

For a point to be the midpoint of a line segment, it must bisect it into two equal segments and be on the line segment (hence, colinear with the endpoints). All four B points are equidistant from points A and C, but aren’t colinear with A and C. Therefore, they aren’t all midpoints of line segment AC.

I hope this helps! :)

5 0
2 years ago
Plz help me tyyysmmm
ch4aika [34]

Answer:

60 \sqrt{2}

7 0
3 years ago
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