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mrs_skeptik [129]
3 years ago
14

Find the distance between the two points rounding to the nearest tenth! PLEASE HELP ASAP!!! :

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0
(-6,-5) (1,-8)
d= √(x₂−x₁)² +(y₂−y₁)²
d= √(1+6)² +(-8+5)²
d= √(7)² +(-3)²
d= √49+9
d= √51
d=7.1
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Brody is purchasing some tools for his workshop. He has a budget of $120 and needs to buy at least 14 tools. Each hammer costs $
STatiana [176]

Answer:

For this case, the first thing we must do is define variables:

x: number of hammers

y: number of wrenches

We write the system of inequations:

10x + 6y <= 120

x + y> = 14

Step-by-step explanation:

5 0
3 years ago
And one US city the taxi cost is five dollars plus $.60 per mile if you are traveling from the airport there is an additional ch
GenaCL600 [577]

Let the number of miles be x.

Then, x miles cost 0.6x.

The initial fixed fee is $5, and the toll is $5.

cost = initial fixed fee + cost per mile + toll

46 = 5 + 0.6x + 5

0.6x + 10 = 46

0.6x = 36

x = 36/0.6

x = 60

You can travel 60 miles.


4 0
3 years ago
Read 2 more answers
Pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Phantasy [73]

Answer:

  • 1 pound- $4.7
  • 2 pounds- $9.4
  • 3 pounds- $14.1
  • 4 pounds- $18.8

Step-by-step explanation:

Just hardware's prices are 0.30 greater per pound, so the equation would be y=4.7x. Substitute x in for each of the values to get the prices above.

3 0
3 years ago
Find the derivative of the function f(x) = (x3 - 2x + 1)(x – 3) using the product rule.
julsineya [31]

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}

Now, we distribute the expression of f(x) and find the derivative afterwards.

f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
3 years ago
Can someone help me plz
wolverine [178]

Answer:

75°

Step-by-step explanation:

Recall: SOH CAH TOA

Reference angle = ? = θ

Side length opposite to reference angle = 27

Hypotenuse length = 28

Apply SOH, which is:

sin(\theta) = \frac{Opposite}{Hypotenuse}

Substitute

sin(\theta) = \frac{27}{28}

\theta = sin^{-1}(\frac{27}{28})

\theta = 75 degrees (nearest degree)

7 0
3 years ago
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