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Brrunno [24]
3 years ago
12

What is the midpoint of AB

Mathematics
1 answer:
emmainna [20.7K]3 years ago
6 0

Therefore, the coordinates of the midpoint of AB are (x1+x22, y1+y22). ... That is the middle point of the line segment joining the points (x1, y1) and (y2, y2) has the coordinates (x1+x22, y1+y22). Solved examples on midpoint formula: 1.

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What two consecutive while numbers does square root of 68 lie?
Fynjy0 [20]
You want to know the two numbers that squared are on either side of 68.

8^2 and 9^2=64 and 81

So the two consecutive numbers are 8 and 9
7 0
3 years ago
9 times the sum of b and 2 is 8
Ksivusya [100]

I suppose you want to solve the following equation for b:

9(b+2)=8

First of all, you need to divide both sides by 9:

b+2 = \dfrac{8}{9}

Then, subtract 2 from both sides:

b = \dfrac{8}{9}-2 = \dfrac{8}{9}-\dfrac{18}{9} = -\dfrac{10}{9}

7 0
3 years ago
Given: ∆ABC, m∠C = 90°
Galina-37 [17]

Answer: 16 units

Step-by-step explanation:

Given that in triangle ABC, m∠C=90,

it means m∠A +∠B= m∠BAC + m∠ABC = 90

m∠ABC = 90 - m∠BAC

Also given that;m∠BAC = 2m∠ABC

So,

m∠BAC = 2(90 - m∠BAC) = 180 - 2m∠BAC

m∠BAC +2m∠BAC = 180

3m∠BAC = 180

m∠BAC=180/3 = 60

m∠ABC = 60/3 = 30

thus,ΔBAC is a 30-60-90 right triangle, in which the ratio of the side lengths is 1:√3:2AC:BC=1:√3, AC=BC/√3BC=24, So,

AC=24/√3=8√3AL bisects angle A =>m∠LAC=30

ΔALC is a 30-60-90 right triangle, in which the ratio of the side lengths is 1:√3:2AC:AL=√3:2AL=2AC/√3=2x8√3/√3=16

8 0
3 years ago
Find the volume of a cone with a base radius of 6 cm and a height of 10 cm write in terms of pie
Savatey [412]

Answer:

  • <u>Volume of the cone is 120 π cm³ </u>

Step-by-step explanation:

Given that Base radius of cone is 6 cm and height is 10 cm and we need to find volume of the cone. Volume of cone is given by:

\\ \:  \:    \dashrightarrow \:  \:  \: \underline{\boxed{\pmb{\sf{Volume_{(cone)} = \dfrac{1}{3} \pi r^2 h }}}}  \\ \\

On Substituting the required values, we get:

\\ \:  \: \dashrightarrow \:  \:  \sf \: Volume_{(cone)} =  \frac{1}{3}  \times  \pi \times  {(6)}^{2}  \times 10 \\  \\  \\  \:  \: \dashrightarrow \:  \:  \sf \: Volume_{(cone)} = \frac{1} {\cancel{3}}  \times  \pi \times  \cancel{36} \times 10 \\ \\   \\  \:  \: \dashrightarrow \:  \:  \sf \: Volume_{(cone)} = \pi \times 12 \times 10 \\  \\  \\  \:  \: \dashrightarrow \:  \:  \sf \: \: { \purple{Volume_{(cone)} =120 \pi \: cm^3 }}\\  \\

  • <u>Volume </u><u>of </u><u>a</u><u> cone </u><u>is </u><u>1</u><u>2</u><u>0</u><u> </u><u>π </u><u>cm³</u>
6 0
2 years ago
Given f(x) = x − 7 and g(x) = x^2 . Find g(f(4)).
garri49 [273]
So basically -3 x 16. Yeilds -48
7 0
4 years ago
Read 2 more answers
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