3 years ago

For what value of k is the trinomial x2 - 6x + k a perfect square?

Mathematics

1 answer:

fenix001 [56]3 years ago

4 0

Answer:

Step-by-step explanation:

$x^2-6x+k\\= x^2-6x + 9 + (-9)+k\\=(x-3)^2+k-9$

So in order this expression to be a perfect square we need k-9=0. Thus k =9.

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