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Alika [10]
3 years ago
12

For what value of k is the trinomial x2 - 6x + k a perfect square?

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

9

Step-by-step explanation:

x^2-6x+k\\= x^2-6x + 9 + (-9)+k\\=(x-3)^2+k-9

So in order this expression to be a perfect square we need k-9=0. Thus k =9.

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