First, we have to see how K2O behaves when it is dissolved in water:
K2O + H20 = 2 KOH
According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:
c(KOH) : c(K2O) = 1 : 2
So,
c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)
Now we can calculate pH:
pOH= -log c(OH⁻) = -log 0.01 = 2
pH= 14-2 = 12
Answer:
5.19 x 10²³ molecules of H₂O
Explanation:
1 mole => 6.023 x 10²³ molecules of H₂O
0.861 mole => 0.861mole x 6.023 x 10²³ molecules of H₂O
= 5.19 x 10²³ molecules of H₂O
Answer:
6.4924249 × 10^-23 g you need to solve it
