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Answer:
1) 0.3g Mg
2)0.5g MgO
3)0.2g O
4)0.01mol Mg & 0.01mol O
5)0.01mol MgO
6) Empirical formula MgO
Explanation:
The mass og Mg is obtained by substracting 24.36g from 24.66g:
24.66 - 24.36 = 0.3g Mg
The ignition of Mg means that it's reacting with oxygen to form an oxide. The increase in the crucible mass after the Mg ignition is due to the addition of oxygen. However, the addition of few drops of water produces a new compound: a hydroxide. According to the oxidation state og Mg (2+), the only magnesium oxide possible is MgO. It happens because the oxidation state of oxygen in oxides is 2-. Which means that just one oxygen atom is required to electrically neutralize one magnesium atom.
We can use a conversion factor to know how much MgO is made from from 0.3 g of Mg:
*
= 0.2g O
Thereby the mass of the oxide is 0.2g O + 0.3g Mg = 0.5g MgO
We convert the mass of oxygen and magnesium to the respective amounts in moles by using conversion factors:
*
= 0.01mol O
*
= 0.01mol Mg
The moles of MgO can be obtained from:
*
= 0.01mol MgO
To obtain the empirical formula, the amount fo moles of each elements must be divided by the smallest one, in this case, 0.01.
The result for both number of Mg atoms and O atoms is 1. This can be interpreted to mean that there is a Mg atom for each O atom forming the formula unit of the compound.
The step when water is added to the compound resulting after heating does not affect the calculations necessary for the magnesium oxide.
Answer:
0
Explanation:
Sodium has a positive 1 charge and chloride has a negative 1 charge. Thus one sodium cation cancels one chloride anion resulting in the formula Na1Cl1 or NaCl. This formula is called the "formula unit" since it represents only one unit of the vast NaCl array or lattice.
The total heat of a process is the sum of all the heat involved in the process. So, the total heat is the sum of all sensible and latent heat in the whole process. For this case, the flow of the release of heat is,
sensible heat from 400 K to the boiling point (351 K) ---> latent heat due to condensation ------> sensible heat from 351 K to melting point (159 K) -----> latent heat due to freezing --------> sensible heat from 159 K to 100 K
Total heat released = 87.53 J/(mol•K)<span> (400 K - 351 K) + </span><span>38560 J/mol + </span><span>112.4 J/(mol•K) ( 351 K - 159 K ) + </span>4900 J/mol + 111.46J / (mol•K) ( 159 K - 100 K) = 75905.91 J / mol
Answer:
The concentration is 0.025 M.
Explanation:
We will use beer law to find the concentration.
A = εmCl
This law relate to the linear equation Y = mx + b in following way,
A = y = absorbance
m = εm = slope or extinction coefficient in beer law.
x = c = concentration
and l is length which is 1 cm
Thus equation can be written as,
A = εmc + b
A - b / εm = c
in order to find the concentration we will abstract the intercept from absorbance and then divide it by the slop.
0.02 - 0.011 / 0.36 = c
c =0.009
c = 0.025 M.