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Juli2301 [7.4K]
2 years ago
8

Calculate the volume of 2.408x1024 molecules of water vapor at STP.

Chemistry
1 answer:
Tom [10]2 years ago
8 0

Answer:

B

Explanation: im not rlly sure you can go with what i said or you dont

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When salt is dissolved in water, which is the solvent and which is the solute
elena55 [62]

Answer:

the solvent is water and the solute is salt

Explanation:

A solute is the component in a solution in the lesser amount. In a NaCl solution, the salt is the solute. A solution may contain more than one solute.

7 0
3 years ago
How can a change to another population could affect births and deaths in the parrot population.
forsale [732]

Answer:

read it first

Explanation:

Population change is governed by the balance between birth rates and death rates. If the birth rate stays the same and the death rate decreases, then population numbers will grow. If the birth rate increases and the death rate stays the same, then population will also grow.

hope it helps

6 0
2 years ago
Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
viva [34]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

6 0
3 years ago
For the decomposition of calcium carbonate, consider the following thermodynamic data (Due to variations in thermodynamic values
In-s [12.5K]

Answer : The temperature in kelvins is, T>1108.695K

Explanation : Given,

\Delta H = 178.5 KJ/mole = 178500 J/mole

\Delta S = 161.0 J/mole.K

Gibbs–Helmholtz equation is :

\Delta G=\Delta H-T\Delta S

As per question the reaction is spontaneous that means the value of \Delta G is negative or we can say that the value of \Delta G is less than zero.

\Delta

The above expression will be:

0>\Delta H-T\Delta S

T\Delta S>\Delta H

T>\frac{\Delta H}{\Delta S}

Now put all the given values in this expression, we get :

T>\frac{178500J/mole}{161.0J/mole.K}

T>1108.695K

Therefore, the temperature in kelvins is, T>1108.695K

7 0
3 years ago
Anaerobic Cellular Respiration
Natasha2012 [34]

Answer:

I A hole

Explanation:

I must be in a museum, because you truly are a work of art

3 0
3 years ago
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