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2 years ago

Calculate the volume of 2.408x1024 molecules of water vapor at STP.

Chemistry

1 answer:

Tom [10]2 years ago

8 0

Answer:

Explanation: im not rlly sure you can go with what i said or you dont

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A man threw a Frisbee which weighs 3 kg with a velocity of 5 m/s. What is the KE in the system? *

arsen [322]

The answer would be 8 just took the test

4 0

2 years ago

Hi ! Could someone help me out with this last part to my chemistry practice ? Thank you !

skelet666 [1.2K]

After 100years, sample is 250g

After 200 years, sample is 125g

After 300years, sample is 62.5 g

7 0

3 years ago

Can anybody check my answer?

anzhelika [568]

Answer:

$\boxed{\text{25. 20 L; 26. 49 K}}$

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}$

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 × 8.314 × T

2026 = 41.57T

$T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}$

6 0

3 years ago

A sample of 0.281 gg of an unknown monoprotic acid was dissolved in 25.0 mLmL of water and titrated with 0.0950 M NaOH NaOH. The

tensa zangetsu [6.8K]

Answer:

98.6 g/mol.

Explanation:

Equation of the reaction

HX + NaOH--> NaX + H2O

Number of moles = molar concentration × volume

= 0.095 × 0.03

= 0.00285 moles

By stoichiometry, 1 mole of HX reacted with 1 mole of NaOH. Therefore, number of moles of HX = 0.00285 moles.

Molar mass = mass ÷ number of moles

= 0.281 ÷ 0.00285

= 98.6 g/mol.

5 0

3 years ago

In the reaction between 15.8 g of NH3 and 22.7 g oxygen, water and nitrogen monoxide are

LenKa [72]

Explanation:

limiting is NH3

NO:27/88g

H2O: 25/09g

4 0

2 years ago