Acceleration =

   (change of speed) / (time for the change).

Change of speed = (speed at the end) - (speed at the beginning)

      =    ( zero ) - (40 m/s)

   = -40 m/s .

Acceleration = (-40 m/s) / (5 seconds)

   = -8 m/s² .

8 0

3 years ago

15 points!

VMariaS [17]

Answer:

$4.12\times 10^{-5}\ J$ .

Explanation:

Given that,

Capacitance, $C=1.4\times 10^{-7}\ F$

Charge stored in the capacitor, $Q=3.4\times 10^{-6}\ C$

We need to find the electric potential energy stored in the capacitor. The formula for the electric potential energy stored in the capacitor is given by :

$E=\dfrac{Q^2}{2C}$

Put all the values,

$E=\dfrac{(3.4\times 10^{-6})^2}{2\times 1.4\times 10^{-7}}\\\\=4.12\times 10^{-5}\ J$

So, the required electric potential eenergy is equal to $4.12\times 10^{-5}\ J$ .

3 0

3 years ago

Please help I don't understand what I'm doing!!

topjm [15]

Answer:

409

Explanation:

7 0

3 years ago

Any two importance of measurement​

Any two importance of measurement