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vlada-n [284]
3 years ago
7

B

Physics
1 answer:
ololo11 [35]3 years ago
3 0

Answer:

Thermal capacity of the object = 720 j/°C

Explanation:

Given:

Specific heat capacity of metal = 360J/(kg°C)

Mass of given object = 2 kg

Find:

Thermal capacity of the object

Computation:

Thermal capacity = Specific heat x Mass

Thermal capacity of the object = Specific heat capacity of metal x Mass of given object

Thermal capacity of the object = 360 x 2

Thermal capacity of the object = 720 j/°C

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Explanation:

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A horizontal black line at left labeled A has a blue arrow pointing down to it and another blue arrow pointing down from it. A h
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The Correct answer is B

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Sort the chemical equations based on the chemical reactions they represent.
Svetradugi [14.3K]

Decomposition reactions are said to be those reactions in which a reactants breakdown into two or more products. The general reaction for decomposition reactions is as follow,

                                         ABC    →    A  +  B  +  C

Specific Examples are as,

                                Water    →     Hydrogen + Oxygen

                                2 H₂O    →           2 H₂     +      O₂

               Calcium carbonate    →     Calcium oxide + Carbon dioxide

                            CaCO₃              →              CaO         +        CO₂

While, Synthetic reactions are said to be those reactions in which two or more reactants combine to form two or more products. The general reaction for synthetic reactions is as follow,

                                         A  +  B  +  C    →    ABC

Specific Examples are as,

                                  Iron + Oxygen     →     Iron Oxide

                                    2 Fe  +  3 O₂      →        2 Fe₂O₃

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                   Potassium + Chlorine      →      Potassium chloride

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4 0
3 years ago
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The terminal speed of a sky diver is 130 km/h in the spread-eagle position and 326 km/h in the nosedive position. Assuming that
SIZIF [17.4K]

Answer:

\frac{A_{slow} }{A_{fast} }=6.2885

Explanation:

Given data

Terminal velocity for spread eagle position vt=130 km/h

Terminal velocity for nosedive position vt=326 km/h

The terminal speed of the diver is given by

v_{t}=\sqrt{\frac{2mg}{CpA} }

Therefore the area is given by

A=\frac{2mg}{Cp(v_{t})^{2}  }\\

Since everything else is constant in the two dives except for the terminal velocity, the ratio between the area in the slow position to the area in the fast position is

\frac{A_{slow} }{A_{fast} }=\frac{326^{2} }{130^{2} }\\\frac{A_{slow} }{A_{fast} }=6.2885

8 0
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PLEASE HURRY
Sophie [7]

Decompose the forces acting on the block into components that are parallel and perpendicular to the ramp. (See attached free body diagram. Forces are not drawn to scale)

• The net force in the parallel direction is

∑ <em>F</em> (para) = -<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>

• The net force in the perpendicular direction is

∑ <em>F</em> (perp) = <em>n</em> - <em>mg</em> cos(21°) = 0

Solving the second equation for <em>n</em> gives

<em>n</em> = <em>mg</em> cos(21°)

<em>n</em> = (0.200 kg) (9.80 m/s²) cos(21°)

<em>n</em> ≈ 1.83 N

Then the magnitude of friction is

<em>f</em> = <em>µn</em>

<em>f</em> = 0.25 (1.83 N)

<em>f</em> ≈ 0.457 N

Solve for the acceleration <em>a</em> :

-<em>mg</em> sin(21°) - <em>f</em> = <em>ma</em>

<em>a</em> = (-0.457N - (0.200 kg) (9.80 m/s²) sin(21°))/(0.200 kg)

<em>a</em> ≈ -5.80 m/s²

so the block is decelerating with magnitude

<em>a</em> = 5.80 m/s²

down the ramp.

5 0
3 years ago
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