All categories

2 years ago

The initial speed of a body is 4.24 m/s. What is its speed after 2.91 s if it accelerates uniformly at -1.76 m/s2

Physics

1 answer:

shutvik [7]2 years ago

6 0

Initial velocity=u=4.24m/s
Time=t=2.91s
Acceleration=a=-1.76m/s^2
Final velocity=v

Using 1st equation of kinematics

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=4.24+2.91(-1.76)$

$\\ \sf\longmapsto v=|4.24-5.12|$

$\\ \sf\longmapsto v=0.8m/s$

You might be interested in

What is the velocity of a penny dropped from the roof after 5 seconds?

Ksivusya [100]

Answer:

49 m/s

Explanation:

Acceleration = velocity / time

You should know accleration due to gravity is 9.8 m/s^2 and you're given t = 5, so you can solve for velocity:

9.8 = v / 5

v = 49

4 0

3 years ago

two asteroids crashed the crash caused both asteroids to change speeds scientist want to use the change

11Alexandr11 [23.1K]

Answer:

The force each one experienced

Explanation:

Hope this helps :)

3 0

2 years ago

Question 5 of 10

ElenaW [278]

Answer:

B it is b because thermal will move from boiling water to the ice

4 0

3 years ago

Explain what happens at a continental continental convergent

sineoko [7]

A subduction zone is formed at a convergent plate boundary when one or both of the tectonic plates is composed of oceanic crust. The denser plate, made of oceanic crust, is subducted underneath the less dense plate, which can be either continental or oceanic crust.

7 0

3 years ago

Please help me with the formular of this question and the solvings.

sweet [91]

Answer:

$\displaystyle T=48.86\ N$

Explanation:

Net Force

The second Newton's law explains how to understand the dynamics of a system where several forces are acting. The forces are vectorial magnitudes which means the x and y coordinates must be treated separately. For each component, the net force must equal the mass by the acceleration, i.e.

$F_{nx}=ma_x$

$F_{ny}=ma_y$

The box with mass m=20 kg is pulled by a rope with a $\theta= 30^o$ angle above the horizontal. It means that force (called T) has two components:

$T_x=Tcos\theta$

$T_y=Tsin\theta$

We'll assume the positive directions are to the right and upwards and that the box is being pulled to the right. There are two forces in the x-axis: The x-component of T (to the right) and the friction force (to the left). So the equilibrium equation for x is

$\displaystyle T\ cos\theta -Fr=m.a$

There are three forces acting in the y-axis: The component of T (upwards), the weight (downwards), and the Normal (upwards). Since there is no movement in the y-axis, the net force is zero and:

$\displaystyle N+T\ sin\theta -mg=0$