Question

The initial speed of a body is 4.24 m/s. What is its speed after 2.91 s if it accelerates uniformly at -1.76 m/s2

Answer 1

• Initial velocity=u=4.24m/s
• Time=t=2.91s
• Acceleration=a=-1.76m/s^2
• Final velocity=v

Using 1st equation of kinematics

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=4.24+2.91(-1.76)$

$\\ \sf\longmapsto v=|4.24-5.12|$

$\\ \sf\longmapsto v=0.8m/s$