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Leona [35]
3 years ago
7

If a force is exerted on an object, is it possible for that object to be moving with constant velocity?

Physics
1 answer:
Anni [7]3 years ago
3 0
After the force is exerted, it will move at a constant velocity until acted upon by another force.
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Choose all of the examples of balanced forces.
SVEN [57.7K]

Answer:

book on flat table

Explanation: the table pushes upward on the book while gravity pulls downward.

6 0
3 years ago
Assuming the starting height is 0.0 m, calculate the potential energy of the cart after it has been elevated to a height of 0.5
Bogdan [553]
The potential energy is most often referred to as the "energy at rest" and is dependent on the elevation of an object. This can be calculated through the equation,

     E = mgh

where E is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. In this item, we are not given with the mass of the cart so we assume it to be m. The force is therefore,

   E = m(9.8 m/s²)(0.5 m) = 4.9m

Hence, the potential energy is equal to 4.9m.
8 0
4 years ago
A 25 N force is used to push a box across a floor against a frictional force of 14 N. The box
Svetlanka [38]

Answer:

m = 44~Kg

Explanation:

<u>Net Force</u>

Newton's second law explains the dynamics principles when a number of forces are applied to an object.

The net force vector is the sum of the individual vector forces applied. The magnitude of the net force is related to the magnitude of the acceleration of the body as follows:

Fn=m.a

Furthermore, the acceleration can be calculated if we know the kinematic behavior of the body:

\displaystyle a=\frac{v_f-v_o}{t}

Where vf, vo, and t are the final speed, initial speed, and time, respectively.

The box is pushed across the floor with a force of 25 N against a frictional force of 14 N.

The net force applied to the box is:

Fn = 25 N - 14 N = 11 N

We also know the box is accelerated from rest (vo=0) to vf=4 m/s in t=16 seconds, thus:

\displaystyle a=\frac{4-0}{16}

a = 0.25~m/s^2

From the equation:

Fn=m.a

We solve for m:

\displaystyle m=\frac{Fn}{a}=\frac{11~N}{0.25~m/s^2}

\mathbf{m = 44~Kg}

3 0
3 years ago
A player strikes a hockey puck giving it a velocity of 30.252 m/s. The puck slides across the ice for 0.267 s after which time i
erica [24]

Answer:

The average drag force is  1.206 (-i)  N

Explanation:

You have to apply the equations of<em> Impulse</em>:

I=FmedΔt

Where I and Fmed (the average force) are vectors.

The Impulse can also be expressed as the change in the <em>quantity of motion</em> (vector P)

I=P2-P1

P=mV (m is the mass and v is the velocity)

You can calculate the quantity of motion at the beggining and at the end of the given time:

Replace the mass in kg, dividing the mass by 1000 to convert it from g to kg.

P1=(0.179kg)(30.252m/s) i=  5.414 i kg.m/s

P2=0.179kg)(28.452m/s) i = 5.092 i kg. m/s

Where i is the unit vector in the x-direction.

Therefore:

I= 5.092 i - 5.414 i = -0.322 i

The average drag force is:

Fmed= I/Δt = -0.322 i/ 0.267s = -1.206 i N

3 0
4 years ago
When all else remains the same, what effect would decreasing the focal length have on a convex lens?
strojnjashka [21]

Answer:

It would cause the lens to produce only real images. It would cause the lens to produce only virtual images. It would make the lens stronger. It would make the lens weaker.

Explanation:

quizlet

5 0
3 years ago
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