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3 years ago

13

Can someone help me with this 7th grade math

1 answer:

Ainat [17]3 years ago

6 0

Answer:

for 7 fabric (square meters), he can make 2 cloaks. for 4 cloaks, he needs 14 fabric (square meters).

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Write an equation of the line that passes through the point (5, -8) with slope 5

Oxana [17]

$\Large\texttt{Answer}$

$equation=$ $\bold{y=5x-33}$

$\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}$

$\Large\texttt{Process}$

<em>⇨ Use the formula below</em>

<em /> $\bf{y-\hfill\stackrel{y \:co-ordinate}{y1}=\hfill\stackrel{slope}{m}(x-\hfill\stackrel{x\:co-ordinate}{x1)}}$

<em>⇨ Substitute the parameters:</em>

<em />

<em /> $\bold{y-(-8)=5(x-5)}$

$\bold{y+8=5x-25}$

$\bold{y=5x-33}$

Hope that helped

4 0

2 years ago

The change in altitude of a bird after 2 __ 1 2 seconds was –41 __ 1 4 feet. What was the average change in altitude of the bird

svlad2 [7]

Answer:

$Average\ Change = -1\frac{7}{10} ft/s$

Step-by-step explanation:

Given

$Altitude\ Change = -4\frac{1}{4} \ ft$

$Time = 2\frac{1}{2}\ s$

Required

Determine the average change

This is calculated as follows:

$Average\ Change = \frac{Altitude\ Change}{Time}$

This gives:

$Average\ Change = \frac{-4\frac{1}{4}}{2\frac{1}{2}}$

$Average\ Change = -4\frac{1}{4}/2\frac{1}{2}$

Convert to improper fractions

$Average\ Change = -\frac{17}{4}/\frac{5}{2}$

Convert to multiplication

$Average\ Change = -\frac{17}{4}*\frac{2}{5}$

$Average\ Change = -\frac{17}{2}*\frac{1}{5}$

$Average\ Change = -\frac{17}{10}$

$Average\ Change = -1\frac{7}{10} ft/s$

8 0

3 years ago

Fiona is 7 years older than Gavin. Alex is 12 years younger than Gavin. If the total of their ages is 73, how old is the younges

sp2606 [1]

Answer:

Think that it’s Alex

7 0

3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Ksju [112]

Answer:converge at $I=\frac{1}{3}$

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int^{\infty}_{3}\frac{1}{x^2}dx$

integration of $\frac{1}{x^2}$ is - $\frac{1}{x}$

$I=\left [ -\frac{1}{x}\right ]^{\infty}_3$

substituting value

$I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]$

$I=-\left [ 0-\frac{1}{3}\right ]$

$I=\frac{1}{3}$

so the value of integral converges at $\frac{1}{3}$

8 0

3 years ago

What is the product of 3.4 × 10−14 and 1.8 × 10^28?

DENIUS [597]

None of the answer matches the correct ans
(3.4×10-14)(1.8×10^28)
20(1.8×10^28)
3.6×10^29

8 0

3 years ago