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nata0808 [166]
3 years ago
5

Graph the function g(x) = 4x–7.

Mathematics
1 answer:
lukranit [14]3 years ago
5 0

Answer:

two dots: (0, -7), (1, -3)

and it's the line

Step-by-step explanation:

just try x=0, g(x)=-7

and x=1, g(x)=-3

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What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
3 years ago
Read 2 more answers
Which is an equation of the line perpendicular to y = -3/4x + 1 and passes through (3, 4)?
topjm [15]

Answer:

Step-by-step explanation:

perp. 4/3

y - 4 = 4/3(x - 3)

y - 4 = 4/3x - 4

y = 4/3x

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=6%20%5Ctimes%20x%20%3D%20%20-%2024" id="TexFormula1" title="6 \times x = - 24" alt="6 \times
Finger [1]
The missing number is 4
8 0
3 years ago
what is the domain of the function: {(1, 3); (3, 5); (5, 7); (7, 9)}? a. {1, 3, 5, 7, 9} b. {1, 3, 5, 7} c. {1, 9} d. {3, 5, 7,
Papessa [141]
B. 1, 3, 5, and 7 are x values. Domain is the x value.
6 0
3 years ago
QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

4 0
3 years ago
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