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Vera_Pavlovna [14]
3 years ago
14

Mark all of the statements that are true.

Mathematics
1 answer:
3241004551 [841]3 years ago
4 0
The correct statements are B and D
Any real value can be entered into the function but the answer will always be -5
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Can someone please help me out
geniusboy [140]
On your paper, you wrote down a^2+b^2 = c^2 which is the pythagorean theorem

You are on the right track. You'll use this equation. In this case
a = 36
b = 18
c = 43
The value of a and b can be swapped. The value of c is always the longest side.

Let's see if a^2+b^2 = c^2 is true or not
a^2 + b^2 = c^2
36^2 + 18^2 = 43^2
1296 + 324 = 1849
1620 = 1849
The last equation is false so the first equation is false when a = 36, b = 18 and c = 43

We do NOT have a right triangle so we do NOT have a rectangle

Answer: No, the table is not "square" (ie, have right angles at the corners)

5 0
4 years ago
In the equation 23×406= 9,338. which number is the product?<br><br>​
krek1111 [17]

Answer:

9,338 is the product of the equation

8 0
3 years ago
Calculator
mixas84 [53]

\text{Given : Which ordered pair is the solution to the system of equations?} \\  \\  \begin{cases}-5x - 3y = 12 \\   y - x = 12 \end{cases}

\text{Solution : According to the question, here let's take these variables as two}  \\  \text{equations then get their value and finally get the answer.} \\  \\  \sf  {1}^{st} \: equation  :  \\ \leadsto \frak{-5x - 3y = 12} \\  \\ \leadsto \frak{-5x = 12 + 3y} \\  \\ \leadsto \frak{x=  \frac{12 + 3y}{-5}} \qquad  \sf ...eq(1) \\  \\  \sf 2^{nd}  \: equation :  \\  \leadsto \frak{y = x - 12} \qquad \sf ...eq(2) \\  \\  \underline{  \frak{finding \: x  }} :  \\  \\  \dashrightarrow \frak{x=  \frac{12 + 3y}{-5}}  \\  \\ \dashrightarrow \frak{x=  \frac{12 + 3(x - 12)}{-5}}  \\  \\  \dashrightarrow \frak{x=  \frac{12 + 3x - 36}{-5}}  \\  \\  \dashrightarrow \frak{-5x=  12 + 3x - 36}  \\  \\  \dashrightarrow \frak{-5x - 3x=   - 24}  \\  \\  \dashrightarrow \frak{-8x =  - 24}  \\  \\  \star \quad \underline{ \boxed{ \green{ \frak{x =  3}}}} \\  \\ \underline{ \frak{ getting \: y}} : \\  \\  \dashrightarrow \frak{y = 3 - 12} \\  \\ \star  \quad\underline{  \boxed{\blue{ \frak{y =  - 9}}}} \\  \\

\green{ \mathbb{HENCEFORTH, \:  THE \:  PAIR \:  IS \:   \pink{\frak{ (3,-9)}}}}

5 0
3 years ago
Please help me!! due in 15 mins
NNADVOKAT [17]
7 hours I believe that’s the answer
8 0
3 years ago
Use a number line to explain why --15 ÷ 3 =-15
Diano4ka-milaya [45]
It's equal to -15 because you are dividing by an negative and if it's only 1 negative number in your equation then your answer will be a negative and if it's 2 negatives then it would be a positive answer
7 0
4 years ago
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