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gulaghasi [49]
3 years ago
5

Sales to customers who use bank credit cards, such as MasterCard and Visa, are generally treated as a. cash sales b. sales retur

ns c. sales on account d. sales when the credit card company remits the cash
Business
1 answer:
sesenic [268]3 years ago
4 0

Answer:

a. cash sales

Explanation:

In economy there exists different types of sales, one of them are cash sales.

Cash sales are sales that are made against cash, this means that the obligation of payment of the buyer is made at the time of the delivery. These sales include:

  • Bills and coins
  • Checks
  • Credit cards

Therefore, sales to customers who use bank credit cards are treated as cash sales

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Harrington Corporation produces three products, A, B, and C. Pertinent information on these products is as follows: ProductSelli
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Answer:

Labour hours constraint :  2a + 2b + 3c ≤ 150

Explanation:

<em>Linear programming is a mathematical model that is used to solve a problem when a firm wants to maximize profit in the midst of multiple resource constraints.</em>

The following steps should be followed:

<em>Step 1: Define the variables</em>

a= the units of product Anchor

b=  the units of product Bearing

c= the units of product Casting

<em>Step 2: Define the constraints:</em>

The constraints represent the limitations which could be resource; in this case machine hours and direct labour hours. Since the constraint in focus is labour hours , so we only consider it.

Subject

Constraints:  Labour hours : 2a + 2b + 3c ≤ 150

Non-negativity constraints a, b , c ≥ 0

Since the total available labour hours is 150 hours then the total consumption hours can either be equal to or less than 150, but can never be higher than 150.

The labour hours constraint  is represented by 2a + 2b + 3c ≤ 150

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Which of the following is a disadvantage to choosing a sole proprietorship business structure?
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Using the continuous compounding equation, if someone invested $5,000 at an interest rate of 3.5%, and someone else invested $5,
UNO [17]

Answer:

Therefore after 16.26 unit of time, both accounts have same balance.

The both account have $8,834.43.

Explanation:

Formula for continuous compounding :

P(t)=P_0e^{rt}

P(t)=  value after t time

P_0= Initial principal

r= rate of interest annually

t=length of time.

Given that, someone invested $5,000 at an interest 3.5% and another one  invested $5,250 at an interest 3.2% .

Let after t year the both accounts have same balance.

For the first case,

P= $5,000, r=3.5%=0.035

P(t)=5000e^{0.035t}

For the second case,

P= $5,250, r=3.5%=0.032

P(t)=5250e^{0.032t}

According to the problem,

5000e^{0.035t}=5250e^{0.032t}

\Rightarrow \frac{e^{0.035t}}{e^{0.032t}}=\frac{5250}{5000}

\Rightarrow e^{0.035t-0.032t}=\frac{21}{20}

\Rightarrow e^{0.003t}=\frac{21}{20}

Taking ln both sides

\Rightarrow lne^{0.003t}=ln(\frac{21}{20})

\Rightarrow 0.003t}=ln(\frac{21}{20})

\Rightarrow t}=\frac{ln(\frac{21}{20})}{0.003}

\Rightarrow t= 16.26

Therefore after 16.26 unit of time, both accounts have same balance.

The account balance on that time is

P(16.26)=5000e^{0.035\times 16.26}

              =$8,834.43

The both account have $8,834.43.

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3 years ago
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