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sergeinik [125]
2 years ago
8

Help i dont know how to do this and i forgot the study guide

Mathematics
1 answer:
dezoksy [38]2 years ago
6 0

Answer:

number 1 is a

Step-by-step explanation:

I don’t know the rest tho but good luck

You might be interested in
ASAP need answer to this system of equations... ILL give brainliest to correct answers only
pshichka [43]

Answer:

(7,12),(-12,-7)

Step-by-step explanation:

x^2 + y^2 = 193

x - y = - 5

x = y - 5

(y - 5)^2 + y^2 = 193

y^2 - 10y + 25 + y^2 = 193

2y^2 - 10y + 25 = 193

2y^2 - 10y + 25 - 193 = 0

2y^2 - 10y - 168 = 0

2*(y^2 - 5y - 84) = 0     This factors into

2*( y - 12) (y + 7) = 0

y = 12    

in which case x = 12 - 5 = 7

y = - 7

in which case x = -7 - 5 = - 12

8 0
3 years ago
Is (6,3) a solution to this system of equations y=3x - 3 3x - y =3
aleksandr82 [10.1K]

Answer:

It is not a solution

Step-by-step explanation:

Plug the point into the equations and check to see if they are true

y=3x - 3

3 = 3(6) -3

3 = 18-3

3 = 15

False

We do not need to check the other equation since this is false

3 0
3 years ago
for employees of Papa Tony's pizza or cleaning up at the end of a busy night. There is a list of 43 complete a task that need to
nydimaria [60]
The answer is 10r3

Hope this helps
3 0
3 years ago
Need help with finding the area of this
dusya [7]
In the given figure, there are two right angled triangles.

Area of triangle = 1/2 × b × h

Area of shaded region = area of larger triangle - area of smaller triangle

= 1/2 × 15 × 18 - 1/2 × 8 × 9

= 135 - 36

= 99 ft^2

Thus, area of shaded region is 99 ft^2.

3 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
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