The balanced molecular equation for the neutralization of sodium hydroxide with sulfuric acid is:
Sodium hydroxide + Sulfuric acid → Sodium sulfate +water
<h3>What is the balanced molecular equation?</h3>
A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products. In other words, the mass and the charge are balanced on both sides of the reaction.
In the given reaction, the reactants have been sulfuric acid and sodium hydroxide. Thus, these are written on the left side of the right arrow. The sodium sulfate and water have been the products and written on the right side of the right arrow.
The balanced molecular equation for the neutralization of sodium hydroxide with sulfuric acid is:
Sodium hydroxide + Sulfuric acid → Sodium sulfate +water
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Answer:
60 g/L is the final concentration of NaI solution .
Explanation:
Molarity of NaI solution before evaporation =
Volume of NaI solution before evaporation =
Molarity of NaI solution after evaporation =
Volume of NaI solution after evaporation =
( dilution)
Molar mass of NaI = 150 g/mol
Concentration of NaI after evaporation :
0.4 M × 150 g/mol = 60 g/L
60 g/L is the final concentration of NaI solution .
<span>so there is a set of DNA for the daughter cell after mitosis has occurred</span>
(anode +) Cu⁰(s) - 2e⁻ → Cu²⁺(aq)
Answer: The charge on a sulfide ion is –2.
Explanation:
