The answers are 3/8 and 1/6.
There are 8 possible outcomes in the sample space for flipping 3 coins. Of those, 3 include two heads and 1 tail. This makes the probability 3/8.
Choosing a quarter for the first coin is 3/10, since there are 3 quarters out of 10 coins. After this, choosing a dime is given by 5/9, since there are 5 dimes out of 9 coins left:
3/10(5/9) = 15/90 = 1/6
The question is asking which formula will give the results
1, 9, 36, 100, 225, ...
for k values of
1, 2, 3, 4, 5, ...
You can try them out to see.
A) for k=2, gives 2*3/2 = 3 . . . not 9
B) for k=1, gives 2^3/3 = 8/3 . . . not 1
C) for k=2, gives (2^2*3^2)/4 = 9 . . . . looks promising
D) for k=1, gives 1*2^3/5 = 8/5 . . . not 1
Selection C is the only viable choice. (And the correct one.)
First, 1950m=1.95km, as 1000m=1km.
Then, 2.5-1.95=0.55km
0.55km = 550m
Answer:
No
Step-by-step explanation:
Janita should not but the table. If the table was 6 feet wide, the widest it can be, the area would be 45 square feet. If the table is 46 7/8 square feet, the width is greater than 6 ft.