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Korolek [52]
3 years ago
7

What is the mode of this data set? {7, 10, 12, 9, 12, 4, 13, 14}

Mathematics
2 answers:
Shkiper50 [21]3 years ago
8 0

5; 7; 19; 24; 10; 17; 21; 6; 22; 5; 9

Arrange: 5; 5; 6; 7; 9; 10; 17; 19; 21; 22; 24

( 5+5+6+7+9+10+17+19+21+22+24 ) / 11

Mean = 145 / 11

Mean = 13,18

Mode = 5

(5 is the only value that appears most often)

Median = 10

(10 is the middle value)

Range = 24 - 5

          =19

( Range is the difference between largest and smallest values)

trapecia [35]3 years ago
3 0
The mode of this set of data is 12
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35 POINTS AVAILABLE
serious [3.7K]

Answer: Circle A, EF is a minor Arc, EAD = 45 degrees, Arc EF= 150 Degrees, and FCE = 210 I guess from the looks of the Picture.

Step-by-step explanation:

6 0
3 years ago
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The points (19,-2) and (0,0) fall on a particular line. What’s is it’s equation in slope intercept form?
Mice21 [21]

Answer:

y=-2/19x

Step-by-step explanation:

slope=(y1-y2)/(x1-x2)=-2/19

y-intercept=0

y=-2/19x+0

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3 years ago
Algebra 1 pls help :)
MaRussiya [10]

Answer:

c

Step-by-step explanation:

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3 years ago
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Find the least common multiple for 6(x+1)^3(x-4)^2 and 10(x+1)^8(x-4)^5
dolphi86 [110]

Answer:

30(x+1)^8 (x-4)^5

Step-by-step explanation

<h3>6(x+1)^{3}(x-4))^{2}=2X3 X (x+1)^3(x-4)^2\\10(x+1)^8(x-4)^5)= 2X5X(x+1)^8 (x-4)^5\\</h3>

In order to find the Least common multiple we write each of the factor only once from each of the expression and for the common expression we take their LCM as maximum of the exponent in  all expressions

as here in the question exponent of (x+1) are 3 and 8 so we take exponent 8

likewise for (x-4) we shall take maximum of 2 and 5 which is 5

so our expression for Least common multiple will be

2X3X5 X (x+1)^8 (x-4)^5

30(x+1)^8 (x-4)^5

7 0
3 years ago
What is the value of x
WITCHER [35]

Answer:

x =68

Step-by-step explanation:

The sum of the angles of a triangle are 180

37+75+x = 180

Combine like terms

112+x = 180

Subtract 112 from each side

112+x-112=180-112

x =68

6 0
3 years ago
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