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mrs_skeptik [129]
3 years ago
12

Solve using substitution: 2x - 3y = -1 y = x - 1

Mathematics
1 answer:
denis-greek [22]3 years ago
8 0

<em>Answer:</em>

<em>x=4 y=3</em>

<em>Step-by-step explanation:</em>

<em>rewrite the equations- y=x-1 2x-3y=-1</em>

<em>solve y=x-1 for y</em>

<em>y=x-1</em>

<em>sub for x-1 for y in 2x-3y=-1</em>

<em>2x-3y=-1</em>

<em>2x-3(x-1)=-1</em>

<em>-x+3=-1</em>

<em>-x+3+-3=-1+-3</em>

<em>-x=-4</em>

<em>divide both sides by -4</em>

<em>x=4</em>

<em>sub 4 for x in y=x-1</em>

<em>y=x-1</em>

<em>y=4-1</em>

<em>y=3</em>

<em>WE ARE VENOM</em>

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Answer:

8th term is 179.15904

Step-by-step explanation:

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r = 60/50 = 72/60 = 6/5

Use the formula

a_{n} = ar^{n - 1}

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a_{8} = 50(6/5)^{8 - 1} \\          = 50(6/5)^{7} \\          =  50(279936/78125)\\          =   179.15904

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3 years ago
Solve with solution...no spam answers pls
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<span>Let's analyze Hannah's work, step-by-step, to see if she made any mistakes. 

</span>In Step 1, Hannah wrote \dfrac{d}{dx} (-3+8x) <span> as the sum of two separate derivatives </span>\dfrac{d}{dx}(-3)+ \dfrac{d}{dx} (8x) <span>using the </span><span>sum rule.
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This step is perfectly fine. 

In Step 2, \dfrac{d}{dx}(8x) was kept as it is, and \dfrac{d}{dx}(-3) was rewritten as 0 using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.

This step is perfectly fine. 

In Step 3, \dfrac{d}{dx} (8x)  was rewritten as \dfrac{d}{dx}(8) \dfrac{d}{dx}(x) supposedly using the constant multiple rule.

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6 0
3 years ago
Read 2 more answers
Help ASAP, question below, 20 points
Talja [164]

Answer:

1 more lawn per hour

Step-by-step explanation:

Brian mows one lawn every hour while logan takes 4 hours to mow 2

Brian:

Hr 1                    1 Lawn

Hr 2                    2 Lawn

Hr 3                    3 Lawn

Hr 4                    4 Lawn

Logan:

Hr 1                    2 Lawn

Hr 2                    4 Lawn

Hr 3                    6 Lawn

Hr 4                    8 Lawn

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Arte-miy333 [17]

Answer:

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To algebraically find this, you'd plug in a 0 for x, since the y intercept is when it crosses the y-axis, which is located at x = 0.

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I hope this helped!

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katen-ka-za [31]

Answer:

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