All categories

2 years ago

How do you convert 0.580 (80repeating) as a fraction?

Mathematics

2 answers:

Stella [2.4K]2 years ago

7 0

9514 1404 393

Answer:

115/198

Step-by-step explanation:

The repeat is 2 digits, so you can multiply the number by 10 to that power.

x = 0.58080...(2-digit repeat)

100x = 58.08080...(2-digit repeat)

Then subtract the original number.

100x -x = 99x = 58.08080... -0.58080... = 57.5

Now, divide by the coefficient of x.

x = 57.5/99 = 115/198

This fraction cannot be reduced, so is the fraction you're looking for.

0.580...(2-digit repeat) = 115/198

_____

Additional comment

The number of 9s in the denominator is the number of repeating digits. If the repeat started at the decimal point, the fraction would be those two repeating digits divided by two 9s (99).

Your number can be considered to be ...

0.58080...(2-digit repeat) = 0.5 + 0.0808...(2-digit repeat)

This will be ...

0.58080... = 1/2 + 8/99 = 99/198 +16/198 = 115/198

Gnom [1K]2 years ago

6 0

Answer:

58/100

Step-by-step explanation:

You might be interested in

SOMEONE PLEASE HELP ASAP!!!!!

Margaret [11]

Answer:

x = 1

y = 1

Step-by-step explanation:

System of Equations

We are given the system of equations:

2x + y = 3

x = 2y - 1

Substituting x in the first equation:

2(2y - 1) + y = 3

Operating:

4y - 2 + y = 3

5y = 3 + 2

y = 5/5 = 1

y = 1

Since:

x = 2y - 1

Then:

x = 2(1) - 1

x = 1

Solution:

x = 1

y = 1

7 0

2 years ago

3+1/2=1 true or false

denis-greek [22]

I am pretty sure its false. I think this becuase 1/2 goes into 3, 6 times, not 1 time. Hope that helps

3 0

2 years ago

Read 2 more answers

Find the real numbers x and y that make the equation true. -3 + yi = x + 6i

Fudgin [204]

The answer is X=-3 and y=6 to make the equation true

4 0

2 years ago

Alli just bought a new car. the car costs $25,000. she has already paid $15,000 with the down payment. she decided she wants to

liraira [26]

Answer: 58 months

Step-by-step explanation:

Let x represent the number of month to pay off the loan

$25,000 - $15,000 + $25x = 200x

Now it is simple algebra

10,000+25x= 200x Subtract 25 x from both sides

10,000 = 175x

x=57.14 month so Really 58 months till they pay it off

5 0

2 years ago

I just need these questions answered, there is no requirement for any explanation! If anybody could assist, that would be great!

koban [17]

Answer:

See explanation

Step-by-step explanation:

Q9. Statement Reason

1) $\angle ABD \cong \angle CBD$ Given

2) $\overline{AB}\cong \overline{CB}$ Given

3) $\overline{BD}\cong \overline {BD}$ Reflexive property

4) $\triangle ABD\cong \triangle CBD$ SAS postulate

5) $\angle A\cong \angle C$ Corresponding parts of congruent triangles are congruent.

Q8. Statement Reason

1) $\overline{AD}\parallel \overline{BC}$ Given

2) $\angle A\cong \angle C$ Alternate interior theorem

3) $\angle AED\cong \angle CEB$ Vertical angles theorem

4) $\overline{AE}\cong \overline{EC}$ Given

5) $\triangle AED\cong \triangle CEB$ ASA postulate

Q7.

1) $\overline{BC}\cong \overline {EF}$ - Given

$\angle CBA\cong \angle FED$ - Given

Pairs of needed sides or pair of needed angles:

$\overline{AB}\cong \overline{DE}$

The postulate or theorem that can be used to prove the triangles are congruent:

SAS postulate

2) $\overline{BC}\cong \overline {EF}$ - Given

$\overline{AC}\cong \overline {DF}$ - Given

Pairs of needed sides or pair of needed angles:

$\overline{AB}\cong \overline{DE}$

The postulate or theorem that can be used to prove the triangles are congruent:

SSS postulate

3) $\overline{BC}\cong \overline {EF}$ - Given

$\angle CBA\cong \angle FED$ - Given

Pairs of needed sides or pair of needed angles:

$\angle ACB\cong \angle DFE$

The postulate or theorem that can be used to prove the triangles are congruent:

ASA postulate

4) $\overline{BC}\cong \overline {EF}$ - Given

$\angle CBA\cong \angle FED$ - Given

Pairs of needed sides or pair of needed angles:

$\angle CAB\cong \angle FDE$

The postulate or theorem that can be used to prove the triangles are congruent:

AAS postulate

Q10. Statement Reason

1) $\angle MCI\cong \angle AIC$ Given

2) $\overline{MC}\cong \overline{AI}$ Given

3) $\overline{CI}\cong \overline{CI}$ Reflexive property

4) $\triangle MCI\cong \triangle AIC$ SAS postulate

4 0

2 years ago