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Oxana [17]
2 years ago
9

Chemical considered hazardous substances are gasoline, water based glue, shot gun shells, sodium chloride, hydraulic acid, paraf

fin wax, fertilizers, fluorescent light bulb's
Chemistry
1 answer:
Montano1993 [528]2 years ago
3 0
Can you provide better insight?
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Answer:

A. power the Calvin cycle.

Explanation:

because it helps to run theblife of plants with easily

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2 years ago
What is one source of human stem cells other than embryos
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2 years ago
Calculate Ho298 for the process
Inga [223]

Explanation:

As per the Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

Hence, according to this law the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Sb + \frac{3}{2}Cl_2 \rightarrow SbCl_{3}    \Delta H^0_1 =  -314 kJ  ..........(1)

SbCl_{3} + Cl_2 \rightarrow SbCl_{5}    \Delta H^0_2 = -80kJ   ..............(2)

The final reaction is as follows:  

Sb + \frac{5}{2}Cl_{2} \rightarrow SbCl_{5}  \Delta H^0_3 = ?  .............(3)

Therefore, adding (1) and (2) we get the final equation (3) and value of \Delta H^{0}_{3} at 298 K will be as follows.

             \Delta H^{0}_{3} = \Delta H^{0}_{1} + \Delta H^{0}_{2}    

                       = -314 kJ + (-80) kJ

                       = -394 kJ

Thus, we can conclude that H^{o} at 298 K for the given process is -394 kJ.

4 0
3 years ago
What is the balanced form of the chemical equation shown below?<br> N2(g) + H2(g) → NH3(g)<br> -
Rom4ik [11]
To balance equations you have to have same number of atoms on both sides of the equation just multiply with a suitable digit

6 0
1 year ago
Oxidation Number of fe in fe3o4​
oee [108]

Oxidation number of fe in the compound...,

Let the oxidation number of (Fe) be x

The oxidation number of oxygen(o) is (-2)

; 3x + 4(-2) = 0...where zero is the total charge on the compound(fe3o4)

; 3x = 8...then divide both sides by 3

Oxidation number of fe is( 2.67 )

4 0
2 years ago
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