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2 years ago

9

Chemical considered hazardous substances are gasoline, water based glue, shot gun shells, sodium chloride, hydraulic acid, paraf

fin wax, fertilizers, fluorescent light bulb's

1 answer:

Montano1993 [528]2 years ago

3 0

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Iron(III) oxide and hydrogen react to form iron and water, like this:

Andru [333]

Answer:mmmm popeyes chicken

Explanation:

6 0

2 years ago

3 waves are shown with a line through their center. The bottom of the first wave is labeled C. A bracket labeled D connects the

Likurg_2 [28]

Answer:Label the parts of this wave.

A:

✔ crest

B:

✔ amplitude

C:

✔ trough

D:

✔ wavelength

Explanation:

8 0

2 years ago

Read 2 more answers

The rate of disappearance of HBr in the gas phase reaction2HBr(g) → H2(g) + Br2(g)is 0.301 M s-1 at 150°C. The rate of appearanc

jok3333 [9.3K]

Answer: 0.151

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2HBr(g)\rightarrow H_2(g)+Br_2(g$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$Rate=-\frac{1d[HBr]}{2dt}=+\frac{1d[H_2]}{2dt}=+\frac{1d[Br_2]}{dt}$

Given: $-\frac{d[HBr]}{dt}]=0.301$

Putting in the values we get:

$\frac{0.301}{2}=+\frac{1d[Br_2]}{dt}$

$+\frac{1d[Br_2]}{dt}=0.151$

Thus the rate of appearance of $Br_2$ is 0.151

8 0

3 years ago

potassium and chlorine react to form potassium chloride. a.it is a redox reaction,explain why. b.see if u can write a balanced e

Elan Coil [88]

Answer:

<em>K</em><em>+</em><em>Cl</em><em /><em>KCl</em>

Explanation:

because the reaction is between metal Potassium and Non-metal Chlorine

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3 years ago

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A solution of NaOH is titrated with H2SO4. It is found that 20.05 mL of 0.3564 M H2SO4 solution is equivalent to 43.42 mL of NaO

Darya [45]

Answer : The concentration of NaOH is, 0.336 M

Explanation:

To calculate the concentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=0.3564M\\V_1=20.05mL\\n_2=1\\M_2=?\\V_2=43.42mL$

Putting values in above equation, we get:

$2\times 0.3564M\times 20.05mL=1\times M_2\times 43.42mL$

$M_2=0.336M$

Thus, the concentration of NaOH is, 0.336 M

3 0

3 years ago