Answer:
<h2>
Kevlar has unique properties such as:</h2><h2><em>
High tensile strength</em>
, <em>
high toughness</em>
, and <em>
chemical stability </em>
at high temperatures<em>
</em>
in polyamides (polymer with repeating unit links by amide bonds.) </h2><h3>
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h3>
Δ What is Kelvar? Δ
~ Kevlar is a heat-resistant and strong synthetic fiber
~ Kevlar is widely used as a friction material in the automotive industry, and a combustion protection material in the aerospace industry. <em>~Looked that up!</em>
<h3>
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h3>
<em>Hope I helped!!!</em>
<em>GL :)</em>
Answer:
0.681 atm
Explanation:
To solve this problem, we make use of the General gas equation.
Given:
P1 = 785 torr
V1 = 2L
T1 = 37= 37 + 273.15 = 310.15K
P2 = ?
V2 = 3.24L
T2 = 58 = 58+273.15 = 331.15K
P1V1/T1 = P2V2/T2
Now, making P2 the subject of the formula,
P2 = P1V1T2/T1V2
P2 = [785 * 2 * 331.15]/[310.15 * 3.24]
P2 = 515.715 Torr
We convert this to atm: 1 torr = 0.00132 atm
515.715 Torr = 515.715 * 0.00132 = 0.681 atm
The answer you looking for is D