Form of energy knows as light energy
1 answer:
You might be interested in
Explanation:
When we increase the temperature of a substance then there will occur an increase in the kinetic energy of its molecules.
Also, K.E =
So, kinetic energy is directly proportional to the temperature.
Hence, when temperature and pressure are kept the same for both oxygen and hydrogen gas then values of their kinetic energy will be the same irrespective of their masses.
Thus, we can conclude that kinetic energy of oxygen molecule is the same as compared to hydrogen molecule.
The question is incomplete, here is the complete question:
Calculate the initial rate for the formation of C at 25°C, if [A]=0.50 M and [B]=0.075 M. Express your answer to two significant figures and include the appropriate units.Consider the reaction
A + 2B ⇔ C
whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table:
The table is attached below as an image.
<u>Answer:</u> The initial rate for the formation of C at 25°C is
<u>Explanation:</u>
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
Rate law expression for the reaction:
where,
a = order with respect to A
b = order with respect to B
- Expression for rate law for first trial:
....(1)
- Expression for rate law for second trial:
....(2)
- Expression for rate law for third trial:
....(3)
Dividing 2 by 1, we get:
Dividing 3 by 1, we get:
Thus, the rate law becomes:
......(4)
Now, calculating the value of 'k' by using any expression.
Putting values in equation 1, we get:
Calculating the initial rate of formation of C by using equation 4, we get:
[A] = 0.50 M
[B] = 0.075 M
Putting values in equation 4, we get:
Hence, the initial rate for the formation of C at 25°C is
