From the calcuation, the percent ionic character of the bond is 70%
<h3>What is percent ionic character?</h3>
The term percent ionic character has to do with the degree of ionic bonding that is contained in a compound. It can be estimated from the electronegativity of each element.
We can use the formula; 100(1 - e^(-ΔEN² / 4))
EN = χB − χA * 100/1
EN = 3.5 - 1.5 = 1
100(1 - e^(-1)^2/4)
= 70%
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Answer:
Reduced species and oxidizing agent: sulfur in the form of sulfate.
Oxidized species and reducing agent: chromium in the form of chromous hydroxide.
Explanation:
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In this case, for the reaction:
We can see that the oxidation states of sulfur and chromium change from +6 to +4 and +3 to +6 respectively; in such a way, since the oxidized species is the same reducing agent because it undergoes an increase in the oxidation state, we infer that chromium is it as it goes from +3 to +6.
Moreover, since the reduced species is the same oxidizing agent because it undergoes a decrease in the oxidation state, we infer that sulfur is it as it goes from +6 to +4.
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The PH of water is 7 because it contains an equal amount of h and oh- ions.
Equation: M1V1 = M2V2
Where M = concentration & V = volume
Step 1: Write down what is given and what you are trying to find
Given: M1 = 1.25M, V1 = 46mL, and V2 = 250mL
Find: M2
Step 2: Plug in the values into the equation
M1V1 = M2V2
(1.25M)(46mL) = (M2)(250mL)
Step 3: Isolate the variable (Divide both sides by 250mL so M2 is by itself)
(1.25M)(46mL) / (250mL) = M2
Answer: M2 = 0.23M
Answer:
1.42m/s
Explanation:
velocity=displacement/time
v=50/35=1.42m/s
