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lyudmila [28]
3 years ago
6

Which answer correctly ranks the atoms in terms of decreasing electronegativity (the highest electronegativity first)? which ans

wer correctly ranks the atoms in terms of decreasing electronegativity (the highest electronegativity first)? c, h, o, n o, n, c, h n, o, c, h o, n, h, c n, o, h, c?
Chemistry
1 answer:
Degger [83]3 years ago
4 0

Answer:

O, N, C, H

Explanation:

Electronegativity of an element is the property that combines the ability of its atom to lose or gain electrons. It measures the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.

On the periodic table, Electronegativity increases across the period but decreases down a group.

To solve the given problem, let us use thE Pauling's table of electronegativities to compare the electronegativities of the elements.

On the table:

C = 2.5

H = 2.1

O = 3.5

N = 3.0

In terms of decreasing electronegativities, the atoms are arranged as:

O N C H

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The length of covalent bond depends upon the size of atoms and the bond order.

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According to the molecular orbital energy-level diagram below, which one of the following statements is not correct about NO, NO
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None of the statement is not correct about NO, NO+, and NO−.

Explanation:

Those molecules whose all subshells are completely filled are diamagnetic.

Those molecules whose any sub-shell is incomplete is termed paramagnetic.

Let us check the magnetism in all three molecules based on molecular orbital theory and Lewis structure

NO= number of electrons 11

It form N=O having configuration 1s2,2s2,2p6,3s1, it has 1 unpaired electron so it is paramagnetic.

Now NO-, number of electrons 12 having configuration 1s2,2s2,2p6,3s2, no unpaired electron hence dimagnetic.

Now NO+, number of electrons is 10 having configuration 1s2,2s2,2p6,3s2, dimagnetic

Let us calculate the bond order of NO-

N0- have 12 electrons as 5 of nitrogen, 6 of oxygen and 1 of - charge on oxygen.

So, bond order = \frac{8-4}{2}

                          = 2 double bonds

bond order of NO+, Number of electrons is 10

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bond order = 3

bond order of NO, number of electrons 11

bond order= \frac{8-3}{2}

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Larger the bond order shorter the bond.

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