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lyudmila [28]
3 years ago
6

Which answer correctly ranks the atoms in terms of decreasing electronegativity (the highest electronegativity first)? which ans

wer correctly ranks the atoms in terms of decreasing electronegativity (the highest electronegativity first)? c, h, o, n o, n, c, h n, o, c, h o, n, h, c n, o, h, c?
Chemistry
1 answer:
Degger [83]3 years ago
4 0

Answer:

O, N, C, H

Explanation:

Electronegativity of an element is the property that combines the ability of its atom to lose or gain electrons. It measures the relative tendency with which the atoms of the element attracts valence electrons in a chemical bond.

On the periodic table, Electronegativity increases across the period but decreases down a group.

To solve the given problem, let us use thE Pauling's table of electronegativities to compare the electronegativities of the elements.

On the table:

C = 2.5

H = 2.1

O = 3.5

N = 3.0

In terms of decreasing electronegativities, the atoms are arranged as:

O N C H

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λ=2167.6 nm

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Explanation:

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ΔE=-2.18*10^{-18} J(\frac{1}{4^{2} } -\frac{1}{7^{2} } )

ΔE=-9.1760*10^-20 J

Now:

|ΔE|=Energy of photon=h*v=h*c/λ

λ=h*c/|ΔE|

λ=\frac{6.63*10^{-34}J.s*3.00*10^{8}m/s  }{9.1760*10^{-20} J }

λ=2.1676*10^-6 m

λ=2167.6*10^-9 m

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

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