Answer:
The bone is compressed to 4.213*10⁻⁶ m.
Explanation:
Given that ,
Mass of the person M = 85 kg,
Length of femur L =0.65 m
Radius of femur r = 0.02 m
To find,
Compression of the bone l = ?
The Young's Modulus is given by Y=
Young's modulus of human femur bone is Y = 9.4 *10⁹ Pa
Rearranging formula ,
l =
Weight supported by femur bone is 85 *0.9 =76.5 Kg
Area = π r² =3.14* (0.02)² = 0.001256 m
The length of compressed bone is
l = = =4213.89 *10⁻⁹
l = 4.213*10⁻⁶ m
The bone is compressed to 4.213*10⁻⁶ m.
Answer:
D. Axial stress divided by axial strain
Explanation:
Lets take rod is pulled by force P
Stress σ = P/A
We know that
σ = ε E
E= Lets take rod is pulled by force P
Stress σ = P/A
We know that
σ = ε E
σ=Axial stress
ε =Axial Strain = ΔL/L
E= σ/ε
E= Axial stress/Axial Strain
So the modulus of elasticity is the ratio of axial stress to axial strain.
σ=Axial stress
ε =Axial Strain = ΔL/L
E= σ/ε
E= Axial stress/Axial Strain
So the modulus of elasticity is the ratio of axial stress to axial strain.
The option D is correct.
Answer:
The phase of mitosis in the illustration is anaphase.
Explanation:
In this phase, the chromosomes separate and move to opposites sides of the cell to prepare for reconstruction and division. These separations are known as sister chromatids.
A. logic, would be your answer i believe!