All categories

3 years ago

The waves are in phase, what must be their path difference in radians?

Physics

1 answer:

babunello [35]3 years ago

6 0

Answer:

180 degrees

Explanation:

if the waves are in phase this means that their frequency is doubled or amplitude is doubled

You might be interested in

How will you separate mixture of metal and nonmetal objects

mojhsa [17]

I think it’s by using a magnet because metals are magnetic

7 0

3 years ago

2000, the Millennium Bridge, a new footbridge over the River Thames in London, England, was opened to the public. However, after

sweet [91]

Answer:

n = 1810

A = 25 mm

Explanation:

Given:

Lateral force amplitude, F = 25 N

Frequency, f = 1 Hz

mass of the bridge, m = 2000 kg/m

Span, L = 144 m

Amplitude of the oscillation, A = 75 mm = 0.075 m

time, t = 6T

now,

Amplitude as a function of time is given as:

$A(t)=A_oe^{\frac{-bt}{2m}}$

or amplitude for unforce oscillation

$\frac{A_o}{e}=A_oe^{\frac{-b(6T)}{2m}}$

$\frac{6bt}{2m}=1$

$b=\frac{m}{3T}$

Now, provided in the question Amplitude of the driven oscillation

$A=\frac{F_{max}}{\sqrt{(k-m\omega_d^2)+(b\omega_d^2)}}$

the value of the maximum amplitude is obtained $(k=m\omega_d^2)$

thus,

$A=\frac{F_{max}}{(b\omega_d}$

Now, for n people on the bridge

Fmax = nF

thus,

max amplitude

$0.075=\frac{nF}{((\frac{m}{3T})2\pi}$

n = 1810

hence, there were 1810 people on the bridge

b) $A=\frac{F_{max}}{(b\omega_d}$

since the effect of damping in the millenium bridge is 3 times

thus,

b=3b

therefore,

$A=\frac{F_{max}}{(3b\omega_d}$

$A=\frac{1}{(3}A_o$

$A=\frac{1}{(3}0.075$

A = 0.025 m = 25 mm

6 0

3 years ago

In a crude model of a rotating diatomic molecule of chlorine (Cl2), the two Cl atoms are 2.00 ✕ 10-10 m apart and rotate about t

Troyanec [42]

Answer:

$1.03723\times 10^{-20}\ J$

Explanation:

r = Radius of atom = $1\times 10^{-10}\ m$

m = Mass of chlorine atom = $5.88\times 10^{-26}\ kg$

$\omega$ = Angular speed = $4.2\times 10^{12}\ rad/s$

The moment of inertia of the system is given by

$I=2mr^2\\\Rightarrow I=2\times 5.88\times 10^{-26}\times (10^{-10})^2\\\Rightarrow I=1.176\times 10^{-45}\ kgm^2$

Kinetic energy is given by

$K=\dfrac{1}{2}I\omega^2\\\Rightarrow K=\dfrac{1}{2}\times 1.176\times 10^{-45}\times (4.2\times 10^{12})^2\\\Rightarrow K=1.03723\times 10^{-20}\ J$

The rotational kinetic energy of one molecule of the atom is $1.03723\times 10^{-20}\ J$

7 0

3 years ago

Estimate the change in the equilibrium melting point of copper caused by a change in pressure of 10 kbar. The molar volume of co

mr Goodwill [35]

Answer:

The change in the equilibrium melting point is 4.162 K.

Explanation:

Given that,

Pressure = 10 kbar

Molar volume of copper $V=8.0\times10^{-6}\ m^3$

Volume of liquid $V=7.6\times10^{-6}\ m^3$

Latent heat of fusion $L= 13.05 kJ$

Melting point =1085°C

We need to calculate the change temperature

Using Clapeyron equation

$\dfrac{\Delta P}{\Delta T}=\dfrac{\Delta H}{T\Delta V}$

Put the value into the formula

$\dfrac{1000\times10^{5}}{\Delta T}=\dfrac{13050}{(1085+273)\times(8.0-7.6)\times10^{-6}}$

$\Delta T=\dfrac{1000\times10^{-5}\times(1085+273)\times(8.0-7.6)\times10^{-6}}{13050}$

$\Delta T=4.162\ K$

Hence, The change in the equilibrium melting point is 4.162 K.

5 0

3 years ago

Do magnets have to touch each other in order to experience a magnetic<br> force? Explain

tiny-mole [99]

Magnets don’t need to touch each other in order to be magnetic because all objects have an attraction however, the closer the magnets get, the more magnetic it is.

4 0

3 years ago