What is the mass and volume of 1000kg/m3 of water?

1. An electron (Q=16x10^-20 C, m=1x10^-30 kg) moving at half a megameter per second up the page enters a region with a uniform m

jek_recluse [69]

Explanation:

It is given that,

Charge on electron, $q=16\times 10^{-20}\ C$

Mass of the electron, $m=9.1\times 10^{-31}\ kg$

Speed of the electron, $v=0.5\ Mm/s=0.5\times 10^6\ m/s$

Magnetic field, B = 1 T (directed out of the page)

Let F is the magnetic force acting on the electron. It is given by :

$F=qvB\ sin\theta$

Here, $\theta=90^{\circ}$

$F=qvB$

$F=16\times 10^{-20}\ C\times 0.5\times 10^6\ m/s\times 1\ T$

$F=8\times 10^{-14}\ N$

Using the right hand rule, the direction of magnetic force is upward to the plane of the paper. Also, the electron will follow the circular path. It is given by :

$r=\dfrac{mv}{qB}$

$r=\dfrac{9.1\times 10^{-31}\ kg\times 0.5\times 10^6\ m/s}{16\times 10^{-20}\ C\times 1\ T}$

$r=2.84\times 10^{-6}\ m$

Hence, this is the required solution.

7 0

3 years ago

Both the electrical force and the gravitational force between two objects share which relationship?

julia-pushkina [17]

Answer:

B. They are inversely proportional to the square of the distance.

Explanation:

The gravitational force between two objects is given by:

$F_G = G \frac{m_1 m_2}{r^2}$

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the distance between the two objects

While the electrical force is given by

$F_E = k \frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1, q2 are the charges of the two objects

r is the distance between the two objects

As we see from the two equations, both forces are inversely proportional to the square of the distance, so the correct option is

B. They are inversely proportional to the square of the distance.

7 0

4 years ago

A material that transmits nearly all the light in a ray because it offers little resistance to the light is

Amanda [17]

The answer is D, transparent

7 0

3 years ago

Read 2 more answers

Explain why is dressing table mirror may become dirsty if wiped with a cloth on a warm day.

gogolik [260]

<h2>Answer:</h2>

<em>When you rub a dry cloth across glass, it creates charged static electricity, which attracts little non-charged dust particles.</em>

6 0

2 years ago

A 120 N force, directed at an angle θ above a horizontal floor, is applied to a 28.0 kg chair sitting on the floor. If θ = 0°, w

ivanzaharov [21]

Answer:

See explanation

Explanation:

Given:-

- The applied force Fa = 120 N

- The angle made with Fa and horizontal = θ

- The mass of chair m = 28.0 kg

Find:-

a) θ = 0 , the horizontal component Fh of the applied force and (b) the magnitude FN of the normal force of the floor on the chair?

If θ = 34.0°, what are (c)Fh and (d)FN?

If θ = 65.0°, what are (e)Fh and (f)FN?

Now assume that the coefficient of static friction between chair and floor is 0.410. What is the maximum force of static friction on the chair if θ is (g) 0°, (h)34.0°, and (i)65.0°?

Solution:-

- We will consider the applied force (Fa) and develop a general expression for Fh as function of θ. Using Trigonometry we have:

Fh = Fa*cos ( θ )

- The normal contact force (N) can be expressed similarly by applying equilibrium conditions on the chair in vertical direction.

N - mg - Fa*sin(θ) = 0

N = m*g + Fa*sin(θ)

For, θ = 0:

Fh = Fa*cos(0) = Fa

Fh = 120 N

N = (28*9.81) + 120*0

N = 274.68 N

For, θ = 34.0:

Fh = Fa*cos(34) = (120)*(0.82903)

Fh = 99.5 N

N = (28*9.81) + 120*sin(34)

N = 341.8 N

For, θ = 65.0:

Fh = Fa*cos(65) = (120)*(0.42261)

Fh = 50.7 N

N = (28*9.81) + 120*sin(65)

N = 383.4 N

- The maximum frictional force (Ff) is given by the following expression:

Ff = N*us

Where, us = coefficient of static friction = 0.41

For, θ = 0:

Ff = (274.68)*(0.41)

Ff = 112.62 N

For, θ = 34:

Ff = (341.8)*(0.41)

Ff = 140.13 N

For, θ = 65:

Ff = (383.4)*(0.41)

Ff = 157.2 N

5 0

3 years ago

What is the mass and volume of 1000kg/m3 of water?​

What is the mass and volume of 1000kg/m3 of water?