Tips to get friends?

A ball hits a wall horizontally at 6m/s and rebounces at 4.4m/s the ball is in contact with wall for 0.04 sec. what is the accel

Svetlanka [38]

Answer:

Acceleration (a) = 40 m/s²

Explanation:

Given:

Initial velocity (u) = 6 m/s

Final velocity (v) = 4.4 m/s

Time taken (t) = 0.04sec

Find:

Acceleration (a) = ?

Computation:

We know that,

⇒ v = u + at

⇒ a = (v - u) / t

⇒ Acceleration (a) = (4.4 - 6) / 0.04

⇒ Acceleration (a) = (-1.6) / 0.04

Acceleration (a) = 40 m/s²

8 0

3 years ago

Georgie was pulling her brother (of mass 16 kg) in a 9.4 kg sled with a constant force of 39 N for one block (128 m). How much w

Genrish500 [490]

Answer:

4992 J

Explanation:

Force, F = 39 N

Distance, s = 128 m

Work done = force x distance

W = 39 x 128

W = 4992 J

Thus, the work done is 4992 J.

7 0

3 years ago

3 resistors are connected in parallel, each with resistance between 1 and 10 Ω. What is NOT a possible value for the overall equ

Leno4ka [110]

Answer:

Therefore,

1/3 ≤ Re ≤ 10/3 ohms

The equivalent resistance CANNOT be any value outside the boundary above

That is

Re CANNOT be greater than 10/3 ohms and CANNOT be less than 1/3 ohms, given that R1,R2,R3 are all between 1 and 10ohms.

Explanation:

For a parallel resistor arrangement.

The equivalent resistance (Re) of the three resistors is given by;

1/Re = 1/R1 + 1/R2 + 1/R3

1/Re = (R2R3 + R1R3 + R1R2)/R1R2R3

Re = R1R2R3/(R2R3 + R1R3 + R1R2)

Therefore, if R1,R2,R3 are between 1-10ohms

We need to calculate the range of values of Re.

Taking the lower bound 1

R1= R2=R3= 1ohms

Re = 1/(1+1+1)

Re = 1/3 ohms

Taking the upper bound 10 ohms

R1= R2=R3= 10 ohms

Re = 1000/(100+100+100)

Re = 1000/300

Re = 10/3 ohms

Therefore,

1/3 ≤ Re ≤ 10/3 ohms

The equivalent resistance CANNOT be any value outside the boundary above

That is

Re cannot be greater than 10/3 ohms and cannot be less than 1/3 ohms, given that R1,R2,R3 are all between 1 and 10ohms.

7 0

3 years ago

What happens when heat is removed from a liquid and it cools?

saul85 [17]

The energy content is decreased and so is the particle speed.

5 0

3 years ago

Read 2 more answers

Earth has a magnetic dipole moment of 8.0 × 1022 J/T. (a) What current would have to be produced in a single turn of wire extend

Bogdan [553]

Answer:

a

The current that would be produced is $I = 6.26 *10 ^8 A$

b

Yes this arrangement can be used to cancel out earths magnetic field at points well above the Earth's surface.This is because this current loop acts as a magnetic dipole for point above the earth surface

c

No this arrangement can not be used to cancel out earths magnetic field at points on the Earth's surface .this because on the earth surface it shifts from its behavior as a magnetic dipole

Explanation:

From the question we are told that

The magnetic moment of earth is $M = 8.0*10 ^{22} J/T$