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lisov135 [29]
3 years ago
7

A small sphere with mass 5.00×10−7 kg and charge +8.00 μC is released from rest a distance of 0.500 m above a large horizontal i

nsulating sheet of charge that has uniform surface charge density σ = +8.00 pC/m2.
Using energy methods, calculate the speed of the sphere when it is 0.100 m above the sheet.
Physics
1 answer:
Damm [24]3 years ago
6 0
<span>Work done on charge is W = Eqd = σ/(2ε₀) x q x d = {(8.00 x 10⁻¹²)/(2 x 8.854187 x 10⁻¹²)} x 3.00 x 10⁻⁶ x (0.650 - 0.250) = 5.42116402J. KE of sphere = 0.5mv² = 0.5 x 5.00 x 10⁻⁷v² = work done by E-field on charge during its fall = 5.42116402→ v = 4657 m/s.</span>
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A thin Nichrome wire connected to an ammeter surrounds a region of time-varying magnetic flux, and the ammeter reads 13 amperes.
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Answer:

The current would be same in both situation.

Explanation:

Given that,

Current I = 13 A

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We need to calculate the induced emf

Using formula of induced emf is

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For N = 1

\epsilon=A\dfrac{dB}{dt}

We need to calculate the current

Using formula of current

i=\dfrac{\epsilon}{R}

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Now, if the number of turn is 22 , then induced emf would be

\epsilon'=NA\dfrac{dB}{dt}

Then the current would be

i'=\dfrac{\epsilon'}{NR}

i'=\dfrac{NA\dfrac{dB}{dt}}{NR}

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i'=i

Hence, The current would be same in both situation.

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3 years ago
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3 years ago
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EXPLANATION:

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As per the options given in the question, the last one is true for an object under balanced forces.

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3 years ago
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e-lub [12.9K]
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