By simplifying
. This will result in a simplified version of
.
The Simplifying Algorithm is a wonderful way to simplify complex mathematics problems. It can be used to solve equations, convert fractions to decimals, and perform many other math operations. In this problem, the Simplifying Algorithm will help you reduce ![\[x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x\]](https://tex.z-dn.net/?f=%5C%5Bx%20-%20%5Cfrac%7B%7B23%7D%7D%7B%7B%7Bx%5E2%7D%7D%7D%20-%20x%20-%2020%20-%20%5Cfrac%7B2%7D%7B5%7D%20-%20x%5C%5D)
Since two opposites add up to 0, remove them from the expression.
![\[ - \frac{{23}}{{{x^2}}} - \frac{{102}}{5} - x\]](https://tex.z-dn.net/?f=%5C%5B%20-%20%5Cfrac%7B%7B23%7D%7D%7B%7B%7Bx%5E2%7D%7D%7D%20-%20%5Cfrac%7B%7B102%7D%7D%7B5%7D%20-%20x%5C%5D)
Write all numerators above the least common denominator 5x2
![\[ - \frac{{115 + 102{x^2} + 5{x^3}}}{{5{x^2}}}\]](https://tex.z-dn.net/?f=%5C%5B%20-%20%5Cfrac%7B%7B115%20%2B%20102%7Bx%5E2%7D%20%2B%205%7Bx%5E3%7D%7D%7D%7B%7B5%7Bx%5E2%7D%7D%7D%5C%5D)
Use the commutative property to reorder the terms so that constants on the left
![\[\frac{{ - 5{x^3} - 115 - 102{x^2}}}{{5{x^2}}}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B%7B%20-%205%7Bx%5E3%7D%20-%20115%20-%20102%7Bx%5E2%7D%7D%7D%7B%7B5%7Bx%5E2%7D%7D%7D%5C%5D)
Rearrange the terms
![\[\frac{{ - 5{x^3} - 102{x^2} - 115}}{{5{x^2}}}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B%7B%20-%205%7Bx%5E3%7D%20-%20102%7Bx%5E2%7D%20-%20115%7D%7D%7B%7B5%7Bx%5E2%7D%7D%7D%5C%5D)
By reording the terms
![\[ - \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}\]](https://tex.z-dn.net/?f=%5C%5B%20-%20%5Cfrac%7B%7B5%7Bx%5E3%7D%20%2B%20102%7Bx%5E2%7D%20%2B%20115%7D%7D%7B%7B5%7Bx%5E2%7D%7D%7D%5C%5D)
Hence, by simplifying this equation, divide both numerator and denominator. This will result in a simplified version of
.
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That’s the answer to your question .
You can this is just the forms basically
The equation to find out the volume in this case is V=x*x*2x, or V=2x^3. Use this we can get that the volumes would be 16, 54, 128, and 250.
$1.50
I hope this is what you need