Projectile motion is characterized by an arc-shaped direction of motion. It is acted upon by two vector forces: horizontal component and vertical component. The horizontal component is in constant velocity motion, while the vertical component is in constant acceleration motion. These two motions are independent of each other.
Now, the total velocity of the space probe at the end of the projectile motion is determined through this equation:
V = √(Vx² + Vy²)
where Vx is the velocity in the horizontal direction and Vy is the velocity in the vertical direction.
Let's find Vx first. Assuming that the space probe was launched at an angle horizontal the Earth's surface, the launching angle is 0°. Thus, the initial velocity is 2.44×10⁴ m/s.
For Vy, the free falling motion is
Vy = √(2gh), where g is 9.81 m/s² and h is the distance traveled vertically by the space probe which represents the radius of the Earth equal to 6.37×10⁶ meters. Therefore,
V = √{(2.44×10⁴)² + [√(2×9.81×6.37×10⁶ )]²}
V = 26,839.14 m/s
Answer:
According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.
Explanation:
Given:
- velocity of plane,
- magnetic field,
- angle between velocity and magnetic field,
- span of the wing,
We know:
According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.
For resistors in series in a DC circuit, the potential difference is proportional to the resistance.
The voltage V across the 7.1 ohm resistor can be found from the proportion
V/7.1 = 12/4.8
V = 7.1*12/4.8 = 17.75
The potential difference at the battery terminals is the sum of the potential differences across the two series resistors.
Vbatt = 17.75 V + 12 V
Vbatt = 29.75 V
The electric potential energy of this system of charges will be +1.44 J. Option E is correct.
<h3>What is the electric potential energy ?</h3>
Electric potential energy stands for the energy that is required to displace a charge in against an electric field.
Given data;
q₁ = 4. 0 µc
q₂ = -8. 0 µc
D(distance between charges) = 0.2 m
The electric potential energy is found as;
The electric potential energy of this system of charges will be +1.44 J.
Hence,option E is correct.
To learn more about the electric potential energy refer:
brainly.com/question/12645463
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