Please help me with this have a great day too also please pick all that are correct and not just one

kirill115 [55]

If you would like to know what is 1200 decreased by 2%, you can calculate this using the following steps:

2% of 1200 = 2% * 1200 = 2/100 * 1200 = 24

1200 - 24 = 1176

The correct result would be 1176.

5 0

4 years ago

Read 2 more answers

The width of the rectangle is 2 more than the length. The area of the rectangle is 63 square inches. How long is the width?

wariber [46]

Answer:

9 inches

Step-by-step explanation:

Area of rectangle= length ×width

Let the length of the rectangle be x inches.

Width of rectangle= (x +2) inches

since the width is 2 more than the length.

63= x(x+2)

63= x(x) +2x

Bringing constant to one side,

x² +2x -63= 0

(x +9)(x-7) = 0 (factorise)

x+9= 0 or x-7= 0

x= -9 or x= 7

(reject)

width of rectangle

= 7+2

= 9 inches

*We reject x= -9 since the length of the rectangle cannot be a negative number.

4 0

4 years ago

How to solve the equation 2x^2 -1 =5x?

Amanda [17]

Answer:

x = 2.68, x = -0.186

Step-by-step explanation:

We are given the following equation that we are to solve:

$2 x ^ 2 - 1 = 5 x$

Rearranging this quadratic equation to get:

$2 x ^ 2 -5 x - 1 = 0$

Solving it by using the quadratic formula as we cannot find any factors for it.

$x= \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-5) \pm (-5)^2-4(2)(-1)}{2(2)}$

$x=\frac{5 \pm\sqrt{25+8} }{4}$

$x=\frac{5+\sqrt{33} }{4}$ , $x=\frac{5-\sqrt{33} }{4}$

x = 2.68, x = -0.186

7 0

3 years ago

Read 2 more answers

Plot and connect the points A (4, 2), B (-3, 2), C(-3, 5), D (4, 5), and find the length of AB.

Phantasy [73]

Answer:

AB = 7

Step-by-step explanation:

The y-coordinate of point A and B is the same.

Therefore, both points lie on the same horizontal line (y = 2).

So determine the distance between them, subtract the x-coordinate of B from the x-coordinate of A:

AB = 4 - -3 = 4 + 3 = 7

However, to calculate the distance between 2 points, regardless if the points are on a horizontal (or vertical) line, you can always use the distance between 2 points formula that is derived from Pythagoras' Theorem, as follows:

let $(x_1,y_1)$ = point A (4, 2)