Answer <u>(assuming it can be in slope-intercept form)</u>:
Step-by-step explanation:
1) First, find the slope of the line between the two points by using the slope formula,
. Substitute the x and y values of the given points into the formula and solve:
Thus, the slope of the line is
.
2) Next, use the point-slope formula
to write the equation of the line in point-slope form. Substitute values for
,
, and
in the formula.
Since
represents the slope, substitute
in its place. Since
and
represent the x and y values of one point the line intersects, choose any of the given points (it doesn't matter which one, it will equal the same thing) and substitute its x and y values into the formula as well. (I chose (-2,0), as seen below.) Then, isolate y and expand the right side in the resulting equation to find the equation of the line in slope-intercept form:
![y-(0)=-\frac{5}{12} (x-(-2))\\y-0 = -\frac{5}{12} (x+2)\\y = -\frac{5}{12} x-\frac{5}{6}](https://tex.z-dn.net/?f=y-%280%29%3D-%5Cfrac%7B5%7D%7B12%7D%20%28x-%28-2%29%29%5C%5Cy-0%20%3D%20-%5Cfrac%7B5%7D%7B12%7D%20%28x%2B2%29%5C%5Cy%20%3D%20-%5Cfrac%7B5%7D%7B12%7D%20x-%5Cfrac%7B5%7D%7B6%7D)
In my calculation is divide it 0.00018333333
and if multiply it well be 6600
Answer:
Slope=1, y-intercept=-1.
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-1-(-4))/(0-(-3))
m=(-1+4)/(0+3)
m=3/3
m=1
y-(-4)=1(x-(-3))
y+4=x+3
y=x+3-4
y=x-1
y=mx+b where m=slope and b=y-intercept
so you have slope of 1 and y-intercept of -1
<span>Which of the following equals 140 to nearest 10
A.134
B.145
C.136
D.146</span>