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If one of two interacting charges is doubled, the force between the charges will double.
Explanation:
The force between two charges is given by Coulomb's law

K=constant= 9 x 10⁹ N m²/C²
q1= charge on first particle
q2= charge on second particle
r= distance between the two charges
Now if the first charge is doubled,
we get 
F'= 2 F
Thus the force gets doubled.
Answer:
25 m
Explanation:
Given:
v₀ = 10 m/s
v = 0 m/s
a = -2 m/s²
Find: Δx
v² = v₀² + 2aΔx
(0 m/s)² = (10 m/s)² + 2 (-2 m/s²) Δx
Δx = 25 m
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10 joules of work is done by the object