a) The car’s speed just after leaving the icy portion of the road is the first part
We have s = ut +
Here s = 130 m, a = -1.2 , u = 76 mile/hr = 33.975 m/s
After 14.72 seconds cars speed is given by v =u +at
u = 33.975m/s, a = -1.2
v = 33.975-1.2*14.72 = 16.31 m/s
So velocity of car on leaving icy surface = 16.31 m/s
b) Time taken after icy surface
0 = 16.31 - 7.10*t
t = 2.23 seconds
Distance traveled during this time
Total distance traveled = 130+18.74 = 148.74 m
c) Total time taken = 14.72+2.23=16.95 seconds