1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
egoroff_w [7]
4 years ago
14

A typical wall outlet voltage is 120 volts in the United States. Personal MP3 players require much smaller voltages, typically 2

35.0 mV. If the number of turns in the primary coil is 3575, calculate the number of turns on the secondary coil of the adapter transformer.
Physics
1 answer:
butalik [34]4 years ago
6 0

Answer:        

Number of turns in secondary will be 7

Explanation:

We have given primary voltage V_p=120volt

Number of turns in the primary is N_p=3575

Secondary voltage is given V_s=235mV=0.235volt

We have to find the number of turns in secondary

We know that \frac{N_p}{N_s}=\frac{V_p}{V_s}

So \frac{3575}{N_s}=\frac{120}{0.235}

N_s=6.60

As the number of turns can not be in decimal so number of turns will be 7

You might be interested in
¿Una persona de 60 corriendo a 4 m/s, tiene más energía cinética que un proyectil de 10 gramos a 300 m/s?
Svet_ta [14]

Explanation:

The question says that "Does a 60 kg person running at 4 m/s have more kinetic energy than a 10 gram projectile at 300 m/s ? "

Speed of a person is 4 m/s

Mass of a person is 60 kg

Kinetic energy of a person is : K=\dfrac{1}{2}mv^2

So,

K=\dfrac{1}{2}\times 60\times 4^2\\\\K=480\ J

Mass of a projectile is 10 grams or 0.01 kg

Speed of a projectile is 300 m/s

Kinetic energy of a projectile is :

K=\dfrac{1}{2}mv^2

K=\dfrac{1}{2}\times 0.01\times (300)^2\\\\K=450\ J

So, it is clear that the kinetic energy of a person is more than that of the kinetic energy of a projectile.

8 0
3 years ago
How do i get the correct answer for 0.429m to mm
krok68 [10]

the answer for 0.429m to mm is 429

6 0
3 years ago
Read 2 more answers
suppose 1 gold bar is 6 cm long, 2 cm high, and 3 cm wide. how many whole gold bars will you be able to fit in a vault with a vo
Gemiola [76]
To determine the number of gold bars that would fit in the vault, determine the volume (v) of a single gold bar.
                              v = l x h x w
where l, h, and w are length, height and width, respectively. Substituting the known values, 
                            v = (6 cm)(2 cm)(3 cm) = 36 cm³
The number of gold bars can be determined by dividing the volume of the vault by the volume of the gold bar,
                                      n = (500 cm³ / 36 cm³) = 13.89
Thus, the maximum number of gold bars in the vault is 13.

5 0
3 years ago
Mercury is similar to Earth's blank ?​
Maurinko [17]

Answer:

density

Explanation:

mecurys is significantly smaller and less massive than earth

7 0
3 years ago
WHAT IS THE S.I UNIT OF MASS
ycow [4]

The SI unit of mass is kilogram (kg)....

4 0
3 years ago
Read 2 more answers
Other questions:
  • please solve this for me ,A garden roller is pulled with a force of 200N acting at an angle of 50 degree with the ground level.f
    11·1 answer
  • Hydrochloric acid and sodium hydroxide are mixed together to form salt and water. During the reaction, the temperature of the so
    8·2 answers
  • A conservative force acts on a particle. We can conclude:
    15·1 answer
  • A 6-inch diameter smooth plastic pipe 3100 ft in length delivers 2.2 cfs of water between two reservoirs. Water viscosity is 11.
    7·1 answer
  • How to understand physics
    5·1 answer
  • Need help! 10 points
    13·1 answer
  • Compute the gravitational force and the electric force between the electron and the proton in the hydrogen atom if they are 5.3
    11·2 answers
  • It is important to stretch all your muscle groups before your exercise program, even those you won’t be using that day.
    7·2 answers
  • A man 2 m tall walks horizontally at a constant rate of 1 m/s toward the base of a tower 23 m tall. When the man is 10 m from th
    14·1 answer
  • A 1.50 kg book is sliding along a rough horizontal surface. At point A it is moving at 3.21 m/s , and at point B it has slowed t
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!