I think b support body weight
Answer:
0.0195 m
Explanation:
= density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³
= diameter of hockey puck = 13 cm = 0.13 m
= height of hockey puck = 2.8 cm = 0.028 m
= density of mercury = 13.6 gcm⁻³ = 13600 kgm³
= depth of puck below surface of mercury
According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck
Weight of mercury displaced = Weight of puck

Answer:
Diffraction: Wave Theory
Interference: Wave Theory
Reflection: both particles and wave theories
Refraction: both particles and wave theories
<span>The pressure a fluid exerts on an object in the fluid is applied in all directions. That is because the particles that make up the fluid can move in any direction. These particles exert forces as they bump into objects in thefluid.</span>
To solve this problem we will apply the concepts related to the double slit experiment. Here we test a relationship between the sine of the deviation angle and the distance between slit versus wavelength and the bright fringe order. Mathematically it can be described as,

Here,
d = Distance between slits
m = Any integer which represent the order number or the number of repetition of the spectrum
= Wavelength
= Angular deviation
Replacing with our values we have,


Part A)

PART B)

