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ICE Princess25 [194]
3 years ago
5

Use the BUCK or UPSC strategy to solve. Show your work.

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0
5 points because that is 5x1
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The usual life of a computer terminal at a university computer center is known to be normally distributed with a mean of 3.25 ye
UNO [17]

Answer:

a) 0.6915; b) 2.83 years

Step-by-step explanation:

For part a,

The formula for a z score is

z=\frac{X-\mu}{\sigma}

Our mean, μ, is 3.25 and our standard deviation, σ, is 0.5.

This gives us

z = (3-3.25)/0.5 = -0.25/0.5 = -0.5

Using a z table, we see that the area under the curve to the left of this is 0.3085.  However we want the area to the right; this means we subtract from 1:

1-0.3085 = 0.6915

For part b,

We look in the cells of a z table to find the value closest to 20%, or 0.2000.  This is 0.2005, which corresponds with a z score of -0.84:

-0.84 = (X-3.25)/0.5

Multiply both sides by 0.5:

0.5(-0.84) = ((X-3.25)/0.5)(0.5)

-0.42 = X-3.25

Add 3.25 to each side:

-0.42+3.25 = X-3.25+3.25

X = 2.83

The advertised life would be 2.83 years.

8 0
3 years ago
WILL MARK FIRST ANSWER BRAINLIEST AND RAISE THE POINTS
bixtya [17]

Answer: x=5

Step-by-step explanation:

3 0
3 years ago
How do you graph −8y = −5x + 40
exis [7]

Answer:

Step-by-step explanation:

download an app called connects go to the app store and look up geometry and scroll down its blue and has a figure 8 on it

8 0
3 years ago
Read 2 more answers
Megan has 25 phone numbers stored in her cell phone. Abby has some phone numbers stored in her cell phone. Together they have a
nikklg [1K]
25+N=61.
N= 36
So there is 36 numbers in Abby's cell phone.
5 0
3 years ago
Read 2 more answers
Lyme disease is spread in the northeastern United States by infected ticks. The ticks are infected mainly by feeding on mice, so
Stels [109]

Answer: 90% confidence interval is; ( - 0.0516, 0.3752 )

 

Step-by-step explanation:

Given the data in the question;  

n1 = 72, n2 = 17

P1 = 54 / 72 = 0.75

P2 = 10 / 17 = 0.5882

so

P_good = 0.75

P_bad = 0.5882

standard ERRROR will be;

SE = √[(0.75×(1-0.75)/72) + (0.5882×(1-0.5882)/17)]

SE = √( 0.002604 + 0.01424)

SE = 0.12978

given confidence interval = 90%

significance level a = (1 - 90/100) = 0.1, |Z( 0.1/2=0.05)| = 1.645   { from standard normal table}

so

93% CI is;

(0.75 - 0.5882) - 1.645×0.12978 <P_good - P_bad<  (0.75 - 0.5882) + 1.645×0.12978

⇒0.1618 - 0.2134 <P_good - P_bad<  0.1618 + 0.2134

⇒ - 0.0516  <P_good - P_bad< 0.3752

Therefore 90% confidence interval is; ( - 0.0516, 0.3752 )

4 0
3 years ago
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