r = radius of the circle traveled by the particle = 76 cm = 0.76 m
T = time period of revolution for the particle = 4.5 s
w = angular velocity of the particle
angular velocity of the particle is given as
w = 2π/T
inserting the values
w = 2 (3.14)/4.5
w = 1.4 rad/s
a = centripetal acceleration of the particle in the circle
centripetal acceleration is given as
a = r w²
inserting the values
a = (0.76) (1.4)²
a = 1.5 m/s²
This behavior helps Betty in <u>intellectual </u>development.
The correct answer (sample response) is:
The image seems to be behind the mirror, but nothing is really there.
Include the following in your response:
The image appears to be behind the mirror.
If someone looks behind the mirror, there is no image there.

Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:

where F is the force applied, and

is the stretch of the spring with respect to its equilibrium position. Using the data, we find

Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
Answer:
α = 0
, w = w₀
Explanation:
Torque is related to angular acceleration by Newton's second law for rotational motion.
τ = I α
Where τ is the torque, I the moment of inertia and α the angular acceleration.
If we apply an external torque for the sum of all torques to be zero, the angular acceleration must fall to zero
α = 0
Since the acceleration is zero, the angular velocity you have at that time is constantly killed.
w = w₀ + α t
w = w₀ + 0