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Goryan [66]
3 years ago
7

Elements that give up electrons easily are called ________

Physics
1 answer:
valina [46]3 years ago
5 0

Elements that give up electrons easily are called <u>metals.</u>

hope this helps!

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A particle travels in a circle of radius 76 cm and completes one revolution in 4.5 s. What is the centripetal acceleration of th
Dimas [21]

r = radius of the circle traveled by the particle = 76 cm = 0.76 m

T = time period of revolution for the particle = 4.5 s

w = angular velocity of the particle

angular velocity of the particle is given as

w = 2π/T

inserting the values

w = 2 (3.14)/4.5

w = 1.4 rad/s

a = centripetal acceleration of the particle in the circle

centripetal acceleration is given as

a = r w²

inserting the values

a = (0.76) (1.4)²

a = 1.5 m/s²

3 0
3 years ago
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Betty is six years old and often asks her parents many questions. Her parents respond to her questions however trivial they may
Brums [2.3K]

This behavior helps Betty in <u>intellectual  </u>development.

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3 years ago
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E20E20: The word “virtual” refers to something that exists in effect but not in actual fact. How does this definition relate to
Lubov Fominskaja [6]

The correct answer (sample response) is:

The image seems to be behind the mirror, but nothing is really there.

Include the following in your response:

The image appears to be behind the mirror.

If someone looks behind the mirror, there is no image there.

|Huntrw6|

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3 years ago
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A certain spring stretches 3 cm when a load of 15 n is suspended from it. how much will the spring stretch if 30 n is suspended
Alik [6]
Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:
k= \frac{F}{\Delta x}
where F is the force applied, and \Delta x is the stretch of the spring with respect to its equilibrium position. Using the data, we find
k= \frac{15 N}{3.0 cm}=5.0 N/cm

Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
\Delta x =  \frac{F}{k}= \frac{30 N}{5.0 N/cm}=6 cm
4 0
3 years ago
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An object has an angular velocity. It also has an angular acceleration due to torques that are present. Therefore, the angular v
shusha [124]

Answer:

 α = 0 ,    w = w₀

Explanation:

Torque is related to angular acceleration by Newton's second law for rotational motion.

        τ = I α

Where τ is the torque, I the moment of inertia and α the angular acceleration.

If we apply an external torque for the sum of all torques to be zero, the angular acceleration must fall to zero

         α = 0

 

Since the acceleration is zero, the angular velocity you have at that time is constantly killed.

           w = w₀ + α t

          w = w₀ + 0

8 0
3 years ago
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