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notka56 [123]
4 years ago
13

What does it mean to say that wolves are social creatures

Physics
1 answer:
Marizza181 [45]4 years ago
5 0
They interact with one another with their facial expressions and body movements all the time
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A meter stick is balanced at the 50 cm mark. You tie 70 N weight at the 30 cm mark. What weight at the 90 cm mark would create a
sveticcg [70]
70x(50-30) = W x (90-50)
1400 = W x 40
W = 35N
5 0
3 years ago
What is sin for the given right triangle?
Rzqust [24]
Sin of a right triangle is opposite divided by hypotenuse
in this case, that is 5/8.6 = 0.581395349<span>
</span>
you can easily remember the trig functions with this acronym:
SOH-CAH-TOA

S: Sine
O: Opposite
H: Hypotenuse

C: Cosine
A: Adjacent
H: Hypotenuse

T: Tangent
O: Opposite
A: Adjacent

5 0
3 years ago
1. How much heat energy ( Q ) is required to heat 2.0 kg of copper from 30.0 oC to 80.0 oC?
djverab [1.8K]

Answer:

Heat capacity, Q = 38500 Joules

Explanation:

Given the following data;

Mass = 2 kg

Initial temperature, T1 = 30°C

Final temperature, T2 = 80°C

Specific heat capacity of copper = 385 J/Kg°C

To find the quantity of heat required;

Mathematically, heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

M represents the mass of an object.

C represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 80 - 30

dt = 50°C

Substituting the values into the formula, we have;

Q = 2 * 385*50

Heat capacity, Q = 38500 Joules

4 0
3 years ago
1. Fill in the blanks. (3 pts)
Usimov [2.4K]

Answer:

a) mass

b) Newtons

c) momentum formula where p stands for momentum, m stands for mass, and v stands for velocity

Hope this helps!

4 0
3 years ago
Read 2 more answers
John(body mass=160pounds) is taking off for a long jump. The average ground reaction force Fg at takeoff is 1400 N pointing forw
slega [8]

Answer:

The free body diagram of John is shown in the attached figure (in the FBD john's mass is supposed to be concentrated at his center of mass and FBD is made of center of mass)

b) As shown in the FBD the ground reaction forces are:

i) In X direction F_{x}=1400cos(35^{o})=1146.81N

ii) In Y direction F_{y}=1400sin(35^{o})=803.0N

c) The respective accelerations in x and y direction's is calculated by newton's second law as indicated under

\sum F_{x}=ma_{x}\\\\\therefore a_{x}=\frac{\sum F_{x}}{m}=\frac{1146.8N}{72.57kg}=15.80m/s^{2}\\\\\sum F_{y}=ma_{y}\\\\\therefore a_{y}=\frac{\sum F_{y}}{m}=\frac{803.00-72.57\times 9.81}{72.57}=1.255m/s^{2}

4 0
3 years ago
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