Question

Giving branliest pls help

Answer 1

Answer:

${( \frac{ {2x}^{4} {y}^{4} }{ {4x}^{2} } )}^{3}$

open the bracket:

$= \frac{ {2x}^{(4 \times 3)} {y}^{(4 \times 3)} }{ {4x}^{(2 \times 3)} }$

simplify:

$= \frac{ {2x}^{12} {y}^{12} }{ {4x}^{6} }$

group x terms together:

$= ( \frac{ {2x}^{12} }{ {4x}^{6} } ) \times {y}^{12} \\ \\ = (\frac{ {x}^{(12 - 6)} }{2} ) \times {y}^{12} \\ \\ = \frac{ {x}^{6} }{2} \times {y}^{12}$

factorise out power 6:

${ \boxed{= \frac{ {(xy {}^{2}) }^{6} }{2} }}$