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GrogVix [38]
3 years ago
13

Equal masses of carbon dioxide (CO2) and oxygen (O2) are mixed. What is the mole

Chemistry
1 answer:
svetoff [14.1K]3 years ago
6 0

The mole fraction of oxygen in this mixture is = 0.5789  which is not listed  in the options. while the mole fraction of carbon dioxide = 0.4211 ( A )

Given that :

Mass of carbon dioxide = mass of oxygen

lets assume the given mass  = x

<u>first step : determine the moles of CO₂ and O₂</u>

moles of CO₂ = mass / molar mass of CO₂

                       = x / 44

moles of O₂  =  mass / molar mass of O2

                     = x / 32

∴ mole fraction of O₂ = moles of O₂ / ( Total moles in the mixture )

                                   = \frac{x}{32} / ( \frac{x}{44} + \frac{x}{32} )

                                   = \frac{44*32*(x)}{32 * 76 *(x)}  = 0.5789

While the mole fraction of Carbon dioxide = 1 - 0.5789 = 0.4211

hence the mole fraction of oxygen in this mixture = 0.5789 while the mole fraction of Carbon dioxide = 0.4211

learn more here : brainly.com/question/15063496

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A thin metallic spherical shell of radius 41.6 cm has a total charge of 8.55 μC uniformly distributed on it. At the center of th
Paul [167]

Answer:

E = 1.2443*10⁶ N/C

Explanation:

R = 41.6 cm = 0.416 m

Q₁ = 8.55 μC = 8.55*10⁻⁶C

Q₀ = 4.43 μC = 4.43*10⁻⁶C

r = 17.9 cm = 0.179 m

K = 9*10⁹ N*m²/C²

Since r < R  we can apply Gauss's Law as follows

E = K*Q₀ / r²

⇒  E = (9*10⁹ N*m²/C²)*(4.43*10⁻⁶C) / (0.179 m)²

⇒  E = 1.2443*10⁶ N/C

5 0
3 years ago
A mixture of c2h2 and ch4 has a total mass of 230.9 g. when this mixture reacts completely with excess oxygen, the co2 and h2o p
Salsk061 [2.6K]
Interesting problem. Thanks for posting.

C2H2 + (3/2)02 ====>  H2O + 2CO2
CH4 +  2O2 =====> 2H2O + CO2

The molar mass of C2H2 = 2*12 + 2*1 = 26
The molar mass of CH4 = 1*12 + 4*1 = 16

The number of moles of C2H2 = x
The number of moles of  CH4 = y
26x + 16y = 230.9 grams

For water we get (from the C2H2). Water has a molar mass of 2*1 + 16 = 18

x*18 See the balanced equation to see what it is the same number of moles as C2H2
From the methane we get
y*18
2*y* 18. Again see the balanced equation to see where that 2 came from.
18x + 36y is the total amount of water. 

Now for the CO2. CO2 has a molar mass of 12 + 2*16 = 44
From C2H2  we get 2*44*x = 88x grams of CO2
From CH4 we get 1*y*44 grams of CO2
88x + 44y for CO2

Now we total to get the grand total of water and CO2
18x + 44y + 88x + 44y = 972.7 grams total.
106x + 88y =  972.7

Two equations, two unknowns, we should be able to solve this problem
26x + 16y = 230.9
106x + 88y = 972.7

I'm not going to go through the math unless you request me to do so. 
x = 8.03 moles
y = 1.38 moles 

The initial amount of C2H2 was 8.03 * 26 = 208.78
The initial amount of CH4 was 16*1.38 = 22.08
The total (as a check is 230.86 which is pretty close to the given amount.
So Methane's mass in the initial givens was 22.08 grams.
6 0
3 years ago
The energy transferred between samples of matter because of a difference in their temperatures is called a. heat. b. thermochemi
Evgesh-ka [11]

Answer:

The energy transferred between samples of matter because of a difference in their temperatures is called a. heat.

Explanation:

The first law of thermodynamics establishes that when two bodies with different temperatures are put in contact they will find thermic equilibrium to a final temperature by transferring heat. Thus the correct answer is (a).

Thermochemistry is the study of the transformations of heat energy on the chemical reactions. Chemical kinetics is the study of the rate of chemical reactions. And temperature is the measure of the heat.

8 0
3 years ago
How long will it take for a 40.0 gram sample of I-131 (half-life = 8.040 days) to decay to 1/100 its original mass? ( PLEASE WIT
masya89 [10]
Idk how long will it
4 0
4 years ago
What would be the major product obtained from hydroboration–oxidation of the following alkenes?
zmey [24]

Answer:

a. 3-methylbutan-2-ol

b. 2-methylcyclohexan-1-ol

Explanation:

For this reaction, we must remember that the hydroboration is an <u>"anti-Markovnikov" reaction</u>. This means that the "OH" will be added at the <em>least substituted carbon of the double bond.</em>

In the case of <u>2-methyl-2-butene</u>, the double bond is between carbons 2 and 3. Carbon 2 has two bonds with two methyls and carbon 3 is attached to 1 carbon. Therefore <u>the "OH" will be added to carbon three</u> producing <u>3-methylbutan-2-ol</u>.

For 1-methylcyclohexene, the double bond is between carbons 1 and 2. Carbon 1 is attached to two carbons (carbons 6 and 7) and carbon 2 is attached to one carbon (carbon 3). Therefore<u> the "OH" will be added to carbon 2</u> producing <u>2-methylcyclohexan-1-ol</u>.

See figure 1

I hope it helps!

8 0
3 years ago
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