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oee [108]
4 years ago
11

Wind turbines are becoming an increasingly popular method of generating a community’s electricity. In wind turbines, wind is use

d to power electric generators. How will an increase in the use of wind turbines affect the availability of wind in the future?
A.) They will pollute the wind, making it unsafe to use.
B.) They will decrease the availability of wind
C.) They will not affect the availability of wind.
D.)They will increase the availability of wind.
Chemistry
2 answers:
ANTONII [103]4 years ago
7 0
<h3>it will not affect the wind</h3>
Tema [17]4 years ago
4 0
The will not affect the wind. When it is windy the wind turns a turbine. Once the wind has gone through the turbine it is just normal wind, none of the wind is lost when this happened
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A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58
Scilla [17]

Answer:

\% O=27.6\%

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}  =0.218molC

- Moles of hydrogen are contained in the 3.922 grams of water:

n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO

Finally, we compute the percent by mass of oxygen:

\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%

Regards.

5 0
4 years ago
Why fluorine would rather bind to calcium than hydrogen
madreJ [45]

Answer:

Because looking at the reactivity series of both elements Calcium is more reactive than hydrogen.

4 0
3 years ago
Which of the following metals (M) will form an ionic compound with nitrogen with the general formula M3N2? Hint: Think about how
Basile [38]

Answer:

See explanation

Explanation:

The question is incomplete but i will try to give you all the necessary guide that you need in order to answer the question.

When compounds are formed, atoms exchange valency. The valency of nitrogen is three while that of the metal is two. The exchange yields M3N2.

If the compound has been specifically mentioned to be a metal, then it must be a group two element. It could be any of Mg, Ca, Sr, Ba or Ra. I did not mention Be here because most of its compounds are covalent.

This will help you to answer the complete question.

5 0
3 years ago
Read 2 more answers
True or false high temperatures reduce activation energy
astra-53 [7]

Answer:

False.

Explanation:

Activation energy ΔGₐ is only directly affected by the shape of the reaction coordinate curve, and is a function of kinetics.

Activation energy ΔGₐ is the minimum amount of energy needed to overcome the process of the reactant into the transition state, and finally the product. Reaction coordinate diagrams are purely based on potential energy of the molecules (electronic structure).

The <em>rate</em> at which the reaction will occur may change due to high temps, but not the actual ΔGₐ. To better understand, look at the Arrhenius equation. Ea (activation energy) is a constant, and is not affected by temperature changes. The rate constant k is only affected by temperature change.

3 0
4 years ago
A reaction requires 22.4l of at stp. You have 32.0l of gas at 398k and 105.6 kpa. Will you have enough gas to carry out the reac
Morgarella [4.7K]
<span>Answer: FALSE:

Explanation:

A reaction requires 22.4l of at STP. You have 32.0l of gas at 398k and 105.6 kpa.

1) STP stands for standard temperature and pressure.

2) Standard temperature is 0°C or 273.15 K

3) Standard pressure is 1 atm or 1013.25 kPa

4) use the ideal gas equation for both contidions

pV = n RT

=> n * R = pV /T

at STP n * R = 1031.25 kPa * 22.4 liter / 273.15 K = 84.5

at T = 398 K, p = 105.6 kPa, and V = 3.2.0 liter:

n * R = 105.6 kPa * 32.0 liter / 398 K = 8.49

Since R is a constant (the Universal Gases Constant), it is evident that the number of moles in the 32.0 liter of gas, at T = 398 K and P = 105.6 kPa is less than the number of moles of the 22.4 liter gas at STP.

There is not enough gas to carry out the reaction.
</span>
4 0
3 years ago
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