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RoseWind [281]
3 years ago
15

What property of water molecules allows water to dissolve many substances

Chemistry
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

Its high polarity

Explanation:

Solvent is the that part of solution which is present in large proportion and have ability to dissolve the solute. In simplest form it is something in which other substance get dissolve. The most widely used solvent is water, other examples are toluene, acetone, ethanol, chloroform etc.

Water is called universal solvent because of high polarity all polar substance are dissolve in it. Hydrogen is less electronegative while oxygen is more electronegative and because of difference in electronegativity hydrogen carry the partial positive charge while oxygen carry partial negative charge.

Water create electrostatic interaction with other polar molecules. The negative end of water attract the positive end of polar molecules and positive end of water attract negative end of polar substance and in this way polar substance get dissolve in it.

Example:

when we stir the sodium chloride into water the cation Na⁺ ions are surrounded by the negative end of water i.e oxygen and anion Cl⁻ is surrounded by the positive end of water i.e hydrogen and in this way all salt is get dissolved.

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How many protons and electrons does oxygen have? What about hydrogen? Draw a model of each atom if that helps you think about th
Tems11 [23]

Answer:

Two electrons fit in the first shell out from the nucleus and eight fit in the second. Every element with more protons than the two of Helium needs to work on shells outside the first one. one you get to ten, you have filled the first two shells.

In a water molecule, oxygen forms one covalent bond with EACH of TWO hydrogen atoms. As a result, the oxygen atom has a stable arrangement of 8 valence electrons. Each hydrogen atom forms only one bond because it needs only two electrons to be stable.

5 0
2 years ago
Which type of wave does not require a medium to travel through?
nlexa [21]

Hello,

I'm not very sure but I think the correct answer is D) Water Wave

I really hope this helps!!!! Happy Holidays!!!! (:

8 0
3 years ago
A solution contains 15 grams of salt per litter of solution. How many grams of salt are in 3.3 litters of solution?​
Verizon [17]

49.5g

Explanation:

Mass of salt = 15g

Volume of solution = 1L

Volume of given solution = 3.3L

Unknown:

Mass of salt in the solution = ?

Solution:

Since we have been given the concentration of the salt in the solution, we can use it to solve the problem.

Concentration; 15g/L

Given;

    In 1L of the solution we have 15g of salt,

In    3.3L of the solution we will have 3.3 x 15 = 49.5g

The salt is the solute and it represents the dissolved substances.

learn more:

Concentration brainly.com/question/4641902

#learnwithBrainly

7 0
3 years ago
NEED ANSWER FAST!
lorasvet [3.4K]

Answer:

B

Explanation:

Molarity = 0.010M

Volume = 2.5L

Applying mole-concept,

0.010mole = 1L

X mole = 2.5L

X = (0.010 × 2.5) / 1

X = 0.025moles

0.025moles is present in 2.5L of NaOH solution.

Molar mass of NaOH = (23 + 16 + 1) = 40g/mol

Number of moles = mass / molar mass

Mass = number of moles × molar mass

Mass = 0.025 × 40

Mass = 1g

1g is present in 2.5L of NaOH solution

6 0
3 years ago
G. whose vapour
german

Answer:

8.33 hours

Explanation:

In order to solve this problem, we must apply Graham's law of diffusion in gases. Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its vapour density. For two gases we can write;

R1/R2=√d2/d1

Where;

R1= rate of diffusion of hydrogen

R2= rate diffusion of unknown gas

d1= vapour density of hydrogen

d2= vapour density of the unknown gas

Volume of hydrogen gas = 360cm^3

Time taken for hydrogen gas to diffuse= 1 hour =3600 secs

R1 = 360 cm^3/3600 secs = 0.1 cm^3 s-1

Vapour density of unknown gas = 25

Vapour density of hydrogen = 1

Substituting values,

0.1/R2 = √25/1

0.1/R2 = 5/1

5R2 = 0.1 × 1

R2 = 0.1/5

R2= 0.02 cm^3s-1

Volume of unknown gas = 600cm^3

Time taken for unknown gas to diffuse= volume of unknown gas/ rate of diffusion of unknown gas

Time taken for unknown gas to diffuse= 600/0.02

Time= 30,000 seconds or 8.33 hours

8 0
3 years ago
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