Answer:- B.
Explanations:- A precipitation reaction is a double displacement reaction in which a solid salt is formed.
If we look at all the given equations then it's only second reaction in which a solid salt (CdS) is formed. In rest of the reactions there is no solid salt formed.
It means A, C and D are not the right choices and so the correct choice is only B.
Here the phase are given for all the products. If the phases are not given then we use the solubility chart to see which reactions would form the precipitate.
Since, the precipitate is formed only in second equation, the correct choice is B.
The electrically charges particles make the material electrically conductive on the atomic level. In metals, the valence electrons are responsible for conduction. More the valence electrons, more the movement of charge, more conductivity.
Answer:
The answer to your question is given below.
Explanation:
Data obtained from the question include:
Sodium, Na => 1s2 2s2 2p6 3s1
Magnesium, Mg => 1s2 2s2 2p6 3s2
Aluminium, Al => 1s2 2s2 2p6 3s2 3p1
Sodium has 1 valence electron. If we remove the valence electron, sodium metal will become an ion. Thus, the electronic configuration becomes
1s2 2s2 2p6.
Magnesium has 2 valence electrons. If we remove the valence electrons, magnesium metal will be an ion. Thus, the electronic configuration becomes
1s2 2s2 2p6.
Aluminium has 3 valence electrons. If we remove the valence electrons, aluminum metal will become an ion. Thus, the electronic configuration becomes
1s2 2s2 2p6.
Answer:
42.8
Explanation:
Let's consider the following reaction at equilibrium.
CO(g) + 2 H₂(g) ⇌ CH₃OH(g)
The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.
The concentration equilibrium constant for this reaction is:
Answer:
I think air is more denser than oxygen