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EleoNora [17]
2 years ago
9

PLEASE HELP IN ONE MINUTE WILL MARK BRAINLIST

Chemistry
1 answer:
IgorC [24]2 years ago
8 0

The freezing point is 18° C

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State the law of conservation of mass
Katen [24]

It’s basically that’s any system that’s closed to all transfers of matter and energy the mass of the system has to remain constant over time because they can’t change meaning you can’t add or remove from it

8 0
2 years ago
Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymer
notsponge [240]

Answer:

C₃H₄O₂ → 50% C; 5.5 % H; 44.5% O

C₄H₆O₂ → 56 % of C; 7 % of H; 37% of O

C₃H₃N → 68 % of C; 6 % of H; 26 % of N

Explanation:

We determine the molar mass of each compound:

C₃H₄O₂ → 72 g/mol

In 1 mol of acrylic acid (72 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

4 moles of H → 1 g/mol . 4 mol = 4 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 36 / 72 = 50 % of C

4 . 100 / 72 = 5.5 % of H

32 . 100 / 72 = 44.5 % of O

C₄H₆O₂ → 86 g/mol

In 1 mol of methyl acrylate (86 g), we have:

4 moles of C → 12 g/mol . 4 mol = 48 g of C

6 moles of H → 1 g/mol . 6 mol = 6 g of H

2 moles of O → 16g/mol . 2 mol = 32 g of O

Then in 100 g of salt, we may have:

100 . 48 / 86 = 56 % of C

6 . 100 / 86 = 7 % of H

32 . 100 / 86 = 37 % of O

C₃H₃N → 53 g/mol

In 1 mol of acrylonitrile (53 g), we have:

3 moles of C → 12 g/mol . 3 mol = 36 g of C

3 moles of H → 1 g/mol . 3 mol = 3 g of H

1 mol of N → 14g/mol . 1 mol = 14 g of N

Then in 100 g of salt, we may have:

100 . 36 / 53 = 68 % of C

3 . 100 / 53 = 6 % of H

14 . 100 / 53 = 26 % of N

3 0
3 years ago
The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wave
timofeeve [1]

Explanation:

It is given that,

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. It means that,

n_i=8

\lambda=3745\ nm

The amount of energy change during the transition is given by :

\Delta E=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

And

\dfrac{hc}{\lambda}=R_H[\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2}]

Plugging all the values we get :

\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{3745\times 10^{-9}}=2.179\times 10^{-18}[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\\dfrac{5.31\times 10^{-20}}{2.179\times 10^{-18}}=[\dfrac{1}{n_f^2}-\dfrac{1}{8^2}]\\\\0.0243=[\dfrac{1}{n_f^2}-\dfrac{1}{64}]\\\\0.0243+\dfrac{1}{64}=\dfrac{1}{n_f^2}\\\\0.039925=\dfrac{1}{n_f^2}\\\\n_f^2=25\\\\n_f=5

So, the final level of the electron is 5.

4 0
3 years ago
State joule thomson effect
tiny-mole [99]

Answer:

In thermodynamics, the Joule–Thomson effect describes the temperature change of a real gas or liquid when it is forced through a valve or porous plug while keeping it insulated so that no heat is exchanged with the environment. This procedure is called a throttling process or Joule–Thomson process

5 0
2 years ago
Is it true that the formula for magnesium sulfate shows that there are four atoms of sulfur
Ulleksa [173]
The chemical formula for magnesium sulfate is MgSO4, so it shows that there are four atoms of oxygen but not sulfur. There is only one atom of sulfur in the formula
4 0
3 years ago
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