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EleoNora [17]
2 years ago
9

PLEASE HELP IN ONE MINUTE WILL MARK BRAINLIST

Chemistry
1 answer:
IgorC [24]2 years ago
8 0

The freezing point is 18° C

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A sample of gas occupies 280 mL when the pressure is 560.00 mm Hg . If the temperature remains constant , what is the new pressu
vichka [17]

Answer : The new pressure if the volume changes to 560.0 mL is, 280 mmHg

Explanation :

According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 560.00 mmHg

P_2 = final pressure = ?

V_1 = initial volume = 280 mL

V_2 = final volume = 560.0 mL

Now put all the given values in the above formula, we get:

560.00mmHg\times 280 mL=P_2\times 560.0 mL

P_2=280mmHg

Therefore, the new pressure if the volume changes to 560.0 mL is, 280 mmHg

3 0
3 years ago
Hello can you help???
MrRissso [65]
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Which group on the periodic table would have zero electronegativity because they have a full octet?
irakobra [83]
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How many joules of energy do you have if you have 0.45 L of water in a can and you heat the 23C water to 55C site:socratic.org
Bess [88]

Answer:

Q = 60192 j

Explanation:

Given data:

Volume of water = 0.45 L

Initial temperature = 23°C

Final temperature = 55°C

Amount of heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  55°C - 23°C

ΔT = 32°C

one L = 1000 g

0.45 × 1000 = 450 g

Specific heat capacity of water is 4.18 j/g°C

Q = m.c. ΔT

Q = 450 g.  4.18 j/g°C.  32°C

Q = 60192 j

4 0
2 years ago
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